anonymous
  • anonymous
Physics dimensional analysis help? #3 on this page: http://www.mrc.uidaho.edu/~atkinson/ECE330_EO/Summer_2009/HW/HW1Fa08_EO330.pdf
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
yeah?
anonymous
  • anonymous
The question is as stated above FWIW I'm trying to switch out of Physics C into Physics B
anonymous
  • anonymous
there should be no math involved in this except logs ... yeah. Everything else is dimensions but I don't know if the number of atoms has dimensions

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anonymous
  • anonymous
what the heck are you reading?
anonymous
  • anonymous
... #3 man
anonymous
  • anonymous
m^3 * m/s^2 *m * kg/m^3 ----------------------------- = should be unit less joules/T *T
anonymous
  • anonymous
do you know logs yet, rym?
anonymous
  • anonymous
yes naturally
anonymous
  • anonymous
Lol... naturally. Hehe.. heh
anonymous
  • anonymous
So not dimensionally correct
anonymous
  • anonymous
Oh wait... not necessarily so if the denom and numerator cancel
anonymous
  • anonymous
okay, so still no
anonymous
  • anonymous
I don't think that's correct
anonymous
  • anonymous
is that equipartition of energy?
anonymous
  • anonymous
(m^3 *(m/s^2)*m* ((kg )/m^3)) ------------------------------ j/T * T = 1 kg m^2/s^2 ---------------------- j 1 kg m/s^2 *m ---------------------- j 1 kg* acceleration *m ---------------------- j 1* newton* meter --------------- j newton*meter=j j/j=1
anonymous
  • anonymous
lib is still on question number 1?
anonymous
  • anonymous
that's 3
anonymous
  • anonymous
@rymdenbarn
anonymous
  • anonymous
So it DOES cancel... it's a yes then?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Thanks

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