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Physics dimensional analysis help? #3 on this page:

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The question is as stated above FWIW I'm trying to switch out of Physics C into Physics B
there should be no math involved in this except logs ... yeah. Everything else is dimensions but I don't know if the number of atoms has dimensions

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Other answers:

what the heck are you reading?
... #3 man
m^3 * m/s^2 *m * kg/m^3 ----------------------------- = should be unit less joules/T *T
do you know logs yet, rym?
yes naturally
Lol... naturally. Hehe.. heh
So not dimensionally correct
Oh wait... not necessarily so if the denom and numerator cancel
okay, so still no
I don't think that's correct
is that equipartition of energy?
(m^3 *(m/s^2)*m* ((kg )/m^3)) ------------------------------ j/T * T = 1 kg m^2/s^2 ---------------------- j 1 kg m/s^2 *m ---------------------- j 1 kg* acceleration *m ---------------------- j 1* newton* meter --------------- j newton*meter=j j/j=1
lib is still on question number 1?
that's 3
So it DOES cancel... it's a yes then?

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