## 28Tylerr 3 years ago Find the additive and multipliactive inverse for each number: 3A. 1.25

1. Shane_B

Do you know what additive and multiplicative inverse means? We can start there...

2. 28Tylerr

I know what it means a little bit but not much. We just started this in our Algerba II

3. Shane_B

Additive inverse is simply the number that when added to the other number equals 0. So $1.25+? = 0$

4. 28Tylerr

25 + 0 = 0? Is thar right?

5. 28Tylerr

That**

6. Shane_B

First, let me clear something up: "3A. 1.25" So the problem is 3A and the value given is 1.25 right?

7. 28Tylerr

Yepp

8. Shane_B

Ok...so what could you add to 1.25 which would result in a value of 0?

9. 28Tylerr

0?

10. Shane_B

1.25 + 0 = 1.25 That's not it :)

11. Shane_B

Since 1.25 is positive...you should see that you must add a negative number to make it 0. Therefore, the answer would be -1.25:$1.25+(-1.25)=0$That's a true equation.

12. 28Tylerr

Right so it would be a -1.25 as a answer?

13. Shane_B

Yes

14. 28Tylerr

Alright so basically just switching a positve to a negative answer.

15. Shane_B

Maybe... If you're original number was -1.25...the additive inverse would actually be +1.25

16. Shane_B

If you're ok with everything above...we can discuss multiplicative inverses

17. 28Tylerr

Yeah thats alright so for 3A it would be -1.25?

18. Shane_B

You still need to do the multiplicative inverse also. Multiplicative inverse is simply defined as the number that when multiplied times the original number result in an answer of 1. In essence, it's going to be the reciprocal of the original value. $(1.25)(\frac{1}{1.25})=1$So the multiplicative inverse of 1.25 is 1/1.25. You could also express this (as well as the additive inverse as a fraction which may be what your teacher wants:$1.25=\frac{5}{4}$So the additive inverse would be :$-\frac{5}{4}$ and the multiplicative inverse would be $\frac{4}{5}$