## 28Tylerr Group Title Find the additive and multipliactive inverse for each number: 3A. 1.25 one year ago one year ago

1. Shane_B Group Title

Do you know what additive and multiplicative inverse means? We can start there...

2. 28Tylerr Group Title

I know what it means a little bit but not much. We just started this in our Algerba II

3. Shane_B Group Title

Additive inverse is simply the number that when added to the other number equals 0. So $1.25+? = 0$

4. 28Tylerr Group Title

25 + 0 = 0? Is thar right?

5. 28Tylerr Group Title

That**

6. Shane_B Group Title

First, let me clear something up: "3A. 1.25" So the problem is 3A and the value given is 1.25 right?

7. 28Tylerr Group Title

Yepp

8. Shane_B Group Title

Ok...so what could you add to 1.25 which would result in a value of 0?

9. 28Tylerr Group Title

0?

10. Shane_B Group Title

1.25 + 0 = 1.25 That's not it :)

11. Shane_B Group Title

Since 1.25 is positive...you should see that you must add a negative number to make it 0. Therefore, the answer would be -1.25:$1.25+(-1.25)=0$That's a true equation.

12. 28Tylerr Group Title

Right so it would be a -1.25 as a answer?

13. Shane_B Group Title

Yes

14. 28Tylerr Group Title

Alright so basically just switching a positve to a negative answer.

15. Shane_B Group Title

Maybe... If you're original number was -1.25...the additive inverse would actually be +1.25

16. Shane_B Group Title

If you're ok with everything above...we can discuss multiplicative inverses

17. 28Tylerr Group Title

Yeah thats alright so for 3A it would be -1.25?

18. Shane_B Group Title

You still need to do the multiplicative inverse also. Multiplicative inverse is simply defined as the number that when multiplied times the original number result in an answer of 1. In essence, it's going to be the reciprocal of the original value. $(1.25)(\frac{1}{1.25})=1$So the multiplicative inverse of 1.25 is 1/1.25. You could also express this (as well as the additive inverse as a fraction which may be what your teacher wants:$1.25=\frac{5}{4}$So the additive inverse would be :$-\frac{5}{4}$ and the multiplicative inverse would be $\frac{4}{5}$