anonymous
  • anonymous
Find the additive and multipliactive inverse for each number: 3A. 1.25
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Shane_B
  • Shane_B
Do you know what additive and multiplicative inverse means? We can start there...
anonymous
  • anonymous
I know what it means a little bit but not much. We just started this in our Algerba II
Shane_B
  • Shane_B
Additive inverse is simply the number that when added to the other number equals 0. So \[1.25+? = 0\]

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anonymous
  • anonymous
25 + 0 = 0? Is thar right?
anonymous
  • anonymous
That**
Shane_B
  • Shane_B
First, let me clear something up: "3A. 1.25" So the problem is 3A and the value given is 1.25 right?
anonymous
  • anonymous
Yepp
Shane_B
  • Shane_B
Ok...so what could you add to 1.25 which would result in a value of 0?
anonymous
  • anonymous
0?
Shane_B
  • Shane_B
1.25 + 0 = 1.25 That's not it :)
Shane_B
  • Shane_B
Since 1.25 is positive...you should see that you must add a negative number to make it 0. Therefore, the answer would be -1.25:\[1.25+(-1.25)=0\]That's a true equation.
anonymous
  • anonymous
Right so it would be a -1.25 as a answer?
Shane_B
  • Shane_B
Yes
anonymous
  • anonymous
Alright so basically just switching a positve to a negative answer.
Shane_B
  • Shane_B
Maybe... If you're original number was -1.25...the additive inverse would actually be +1.25
Shane_B
  • Shane_B
If you're ok with everything above...we can discuss multiplicative inverses
anonymous
  • anonymous
Yeah thats alright so for 3A it would be -1.25?
Shane_B
  • Shane_B
Yes, that's additive inverse answer.
Shane_B
  • Shane_B
You still need to do the multiplicative inverse also. Multiplicative inverse is simply defined as the number that when multiplied times the original number result in an answer of 1. In essence, it's going to be the reciprocal of the original value. \[(1.25)(\frac{1}{1.25})=1\]So the multiplicative inverse of 1.25 is 1/1.25. You could also express this (as well as the additive inverse as a fraction which may be what your teacher wants:\[1.25=\frac{5}{4}\]So the additive inverse would be :\[-\frac{5}{4}\] and the multiplicative inverse would be \[\frac{4}{5}\]

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