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for (a) x cannot be 0 if not its undefined

range is y cannot be 1

(b) is x cannot be -1 if not denominator is 0 n 1/0 is undefined

range is y cannot be 0

Can you show me how did you get that?

for a) I got (1/x) + 1 >= 0 ? Did I set it up correctly?

http://cs.gmu.edu/cne/modules/dau/calculus/domains_ranges/dom2_frm.html

the denominator cannot be zero and function is only 1 to 1

Do I need to think about the negatives as well?

yes.. for example 1/(x+1).. ur x cannot be negative one cause -1 +1 = 0

For a) if the denominator was negative, it would make the equation inside the sqrt negative

umm brother... its 1 OVER x...

-2, -3, etc...

even if x is -100000000000 its 1 OVER it.. thats like 0.00000000000 bla bla bla

Oh nvm