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moongazer

  • 2 years ago

What are the products ? MgO+H2O --> KClO3 + O2 --> CuSO4 + Fe --> Ba(NO3)2 + K2CrO4 --> Zn + Pb(NO3)2 --> Cu + Pb(NO3)2 -->

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  1. moongazer
    • 2 years ago
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    are these reactions correcT?

  2. moongazer
    • 2 years ago
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    I got it from our experiment.

  3. lgbasallote
    • 2 years ago
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    metal oxide + water always results to hydroxide. Since MgO is a metal oxide, MgO + H20 -> MG(OH)2 does that make sense?

  4. lgbasallote
    • 2 years ago
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    that's supposed to be Mg(OH)2

  5. moongazer
    • 2 years ago
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    how did you do that?

  6. lgbasallote
    • 2 years ago
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    which one?

  7. moongazer
    • 2 years ago
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    wait, I think I got it. you said: metal oxide + water always results to hydroxide so you placed (OH)2 after Mg is it always metal oxide + (OH)2? I mean you will "always" just stick (OH)2 after the metal oxide if the reaction is metal oxide + water?

  8. lgbasallote
    • 2 years ago
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    not always stick (OH)2 it has 2 because the charge of Mg is 2+. So by the "criss-cross" method you get (OH)2 make sense?

  9. lgbasallote
    • 2 years ago
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    you just stick OH after the metal oxide then apply the necessary subscripts

  10. lgbasallote
    • 2 years ago
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    okay...i need to go for a while

  11. moongazer
    • 2 years ago
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    ok, thanks for the help :)

  12. moongazer
    • 2 years ago
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    could you do another one from my question? I'll just try to answer the others :)

  13. abayomi12
    • 2 years ago
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    let me send you some the element and you will choose the correct one cause i don't know chemistry

  14. UnkleRhaukus
    • 2 years ago
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    \[\text{Cu}\text{SO}_4 + \text{Fe} \rightarrow \text{Fe}\text{SO}_4+\text{Cu}\]

  15. lgbasallote
    • 2 years ago
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    okay. im back

  16. abayomi12
    • 2 years ago
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    2Fe+3Cl2=2FeCl3 2Fe + 3Cl2 = 2FeCl3 2Fe+3Cl2=2FeCl3 2Fe + 3Cl2 = 2FeCl3 2Fe + 3Cl2 = 2FeCl3 2Fe + 3Cl2 = 2FeCl3 2Fe + 3Cl2 = 2FeCl3 2Fe + 3Cl2 = 2FeCl3 2Fe + 3Cl2 = 2FeCl3 2Fe + 3Cl2 = 2FeCl3 2KO2 + 2H2O = 4KOH + 3O2 4KO2 + 2H2O = 4KOH + 3O2 2KO2 + 2H2O = 4KOH + 3O2 4KO2 + 2H2O = 4KOH + 3O2 2Mg + O2 = 4MgO 2Mg + O2 = 2MgO 2NaCl + H2SO4 = Na2SO4 + 2HCl 2NaCl + H2SO4 = Na2SO4 + 2HCl 2Al + 6NaOH = 2Na3AlO3 +3H2 2Al + 6NaOH = 2Na3AlO3 + 3H2 2KMnO4 + FeSO4 + H2SO4 = 2MnS04 + K2SO4 + Fe2(SO4)3 + H2O 2KMnO4 + 62FeSO4 + 40H2SO4 = 2MnS04 + K2SO4 + 31Fe2(SO4)3 + 40H2O

  17. lgbasallote
    • 2 years ago
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    lol wow

  18. UnkleRhaukus
    • 2 years ago
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    what is all that @abayomi12?

  19. lgbasallote
    • 2 years ago
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    Cu + Pb(NO3)2 does not react. However *if* it does then it will just be a single displacement reaction Cu + Pb(NO3)2 --> Cu (NO3)2 + Pb

  20. abayomi12
    • 2 years ago
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    i told you i don't know much about chemistry just trying to put that maybe he can choose the correct one i have alot here i can send them if you want

  21. lgbasallote
    • 2 years ago
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    as for Zn + Pb(NO3)2 <--this is just single displacement reaction

  22. lgbasallote
    • 2 years ago
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    Ba(NO3)2 + K2CrO4 <--this is double displacement reaction

  23. moongazer
    • 2 years ago
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    @lgbasallote I think I already know how to get it. I'll try to answer all of it. please check my answers :)

  24. lgbasallote
    • 2 years ago
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    sure

  25. lgbasallote
    • 2 years ago
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    tag me when you have the list

  26. moongazer
    • 2 years ago
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    ok :)

  27. moongazer
    • 2 years ago
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    I think "KClO3 + O2" should be KClO3 + MnO2 because it is stated that "place a mixture of KClO3 and MnO2 in a test tube." then I heated it

  28. lgbasallote
    • 2 years ago
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    probably...i dont know much about your chemistry experiment lol

  29. moongazer
    • 2 years ago
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    MgO+H2O --> Mg(OH)2 KClO3 + MnO2 --> CuSO4 + Fe --> Cu + FeSO4 Ba(NO3)2 + K2CrO4 --> BaCrO4 + K2(NO3)2 Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb Cu + Pb(NO3)2 --> Cu(NO3)2 + Pb

  30. moongazer
    • 2 years ago
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    @lgbasallote

  31. lgbasallote
    • 2 years ago
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    yes. sounds right to me

  32. lgbasallote
    • 2 years ago
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    btw...i forgot to mention...dont forget to balance your equations

  33. moongazer
    • 2 years ago
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    ok thanks :)

  34. lgbasallote
    • 2 years ago
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    welcome

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