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Calculate an integral

Mathematics
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1 Attachment
Have you tried u-sub?
try u = 9-x^2

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Other answers:

No, sub u=x^2
I'm pretty sure mine still works... Both are fine...
my substitution become like this...
1 Attachment
Well you can trig sub if you want but that makes it needlessly complicated IMO.
emm what u suggest ?
I told u. u = 9-x^2.
Do you know how to u-sub?
\[u=x^2; \frac{ 1 }{ 2 }du = xdx\]
Again, either mine or james' work, since he keeps insisting....
you will get: \[\frac{ 1 }{ 2 }\int\limits_{0}^{1.6}(9-u)^{3/2}u du\]
for the integrand \[(9-u)^{3/2}u\] sub s=9-u and ds=-du
at this point you can expand the integrand and solve.
@jamesHayek I msged you but I'll tell you again: We don't want to give them most of the problem.
vf321, this is a site to help. Not bicker. Show your work to help her.
@jamesHayek help, not do homework for. But fine, this is not getting us anywhere. Let's stop arguing.
i am following ur step now. thx. trying to get the right answer
i will try both method

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