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vf321 Group TitleBest ResponseYou've already chosen the best response.1
Have you tried usub?
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
try u = 9x^2
 2 years ago

jamesHayek Group TitleBest ResponseYou've already chosen the best response.1
No, sub u=x^2
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
I'm pretty sure mine still works... Both are fine...
 2 years ago

akl3644 Group TitleBest ResponseYou've already chosen the best response.0
my substitution become like this...
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
Well you can trig sub if you want but that makes it needlessly complicated IMO.
 2 years ago

akl3644 Group TitleBest ResponseYou've already chosen the best response.0
emm what u suggest ?
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
I told u. u = 9x^2.
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
Do you know how to usub?
 2 years ago

jamesHayek Group TitleBest ResponseYou've already chosen the best response.1
\[u=x^2; \frac{ 1 }{ 2 }du = xdx\]
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
Again, either mine or james' work, since he keeps insisting....
 2 years ago

jamesHayek Group TitleBest ResponseYou've already chosen the best response.1
you will get: \[\frac{ 1 }{ 2 }\int\limits_{0}^{1.6}(9u)^{3/2}u du\]
 2 years ago

jamesHayek Group TitleBest ResponseYou've already chosen the best response.1
for the integrand \[(9u)^{3/2}u\] sub s=9u and ds=du
 2 years ago

jamesHayek Group TitleBest ResponseYou've already chosen the best response.1
at this point you can expand the integrand and solve.
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
@jamesHayek I msged you but I'll tell you again: We don't want to give them most of the problem.
 2 years ago

jamesHayek Group TitleBest ResponseYou've already chosen the best response.1
vf321, this is a site to help. Not bicker. Show your work to help her.
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
@jamesHayek help, not do homework for. But fine, this is not getting us anywhere. Let's stop arguing.
 2 years ago

akl3644 Group TitleBest ResponseYou've already chosen the best response.0
i am following ur step now. thx. trying to get the right answer
 2 years ago

akl3644 Group TitleBest ResponseYou've already chosen the best response.0
i will try both method
 2 years ago
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