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MyammecutieBest ResponseYou've already chosen the best response.2
Think of any vertex. It can't connect to itself, nor the two neighboring vertices already connected by edges, but that still leaves 9 vertices to connect to. 12 vertices each connected to 9 other vertices would seem to imply 108 diagonals... except you are doublecounting everything (a diagonal from A to B is the same as a diagonal from B to A). So divide this number by 2. Note: The general formula for the number of diagonals in an ngon is: n(n3) / 2 Answer: 54 diagonals
 one year ago
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