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Lulu212Best ResponseYou've already chosen the best response.0
do u know how to solve this ?
 one year ago

jeanlouieBest ResponseYou've already chosen the best response.0
sin(2x) is more interesting :)
 one year ago

OmniscienceBest ResponseYou've already chosen the best response.0
Is it sin^2x + 4sinx + 3 = 0 ?
 one year ago

OmniscienceBest ResponseYou've already chosen the best response.0
dw:1345778720492:dw i dont know why latex is not working..
 one year ago

ash2326Best ResponseYou've already chosen the best response.0
@Lulu212 Is it \(\sin 2x \ or \ \sin^2 x\)?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
\[sin2x = 2sinxcosx\] \[ 2sinxcosx + 4sinx + 3 = 0 \]
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
have you tried that yet?
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
hm...hm.... u need...to find the General soln of this....!
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
@UnkleRhaukus @Hero @jim_thompson5910 @myininaya
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[ \sin(2x) + 4\sin (x) + 3 = 0\] \[ 2\sin(x)\cos(x) + 4\sin (x) + 3 = 0\] \[2\sin (x)\left(\cos(x)+2\right)+3=0\] \[2\sin (x)\left(\cos(x)+2\right)=3\] \[\cos(x)+2=\frac{3}2\csc(x)\] i dont know
 one year ago

HeroBest ResponseYou've already chosen the best response.1
I don't understand why @UnkleRhaukus can't finish it
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
Can u Finish @Hero i am also stuck..there
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
hmm http://www.wolframalpha.com/input/?i=sin2x+%2B+4sin+x+%2B+3+%3D+0 i dont think its possible..
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
i think..tthere is mistake in question..))))
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
@Lulu212 can u check ur question...))
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
I think it should be \(sin^2x + 4sinx +3 =0\)
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
then \(u=sinx\) more reasonable
 one year ago

HeroBest ResponseYou've already chosen the best response.1
I'm inclined to agree with @Mimi_x3
 one year ago

manishsatywaliBest ResponseYou've already chosen the best response.0
this question can be solved ............why u guys are worrying????????
 one year ago

nickhouraneyBest ResponseYou've already chosen the best response.0
it cant be solved just endless ways of writing the equation
 one year ago

panlac01Best ResponseYou've already chosen the best response.0
what are we solving for? LOL. that equation needs to be written precisely in a way that we all can agree to what it is.
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[\sin^2x+4\sin x+3=0\] \[u^24u+3=0\] \[u=\frac{(4)\pm\sqrt{(4)^24\times(1)\times(3)}}{2(1)}\] \[u=2\pm\frac{\sqrt{4}}{2}\]\[u=2\pm1\]\[u=1,3\] \[(1)^2+4(1)+3=0,\qquad\qquad 3^24(3)+3=0\]\[8=0,\qquad\qquad\qquad 3^24(3)+3=0\]\[\text{false}\qquad\qquad\qquad 912+3=0\]\[\qquad\qquad\qquad\qquad0=0\]\[\qquad\qquad\qquad\text{true}\]
 one year ago

panlac01Best ResponseYou've already chosen the best response.0
the equation toolbar in this thing sucks hairy ______. how do you write it so neatly like that?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
so \(u=\sin(x)=3\) \[x=\arcsin (3)\] ... this question is very confusing \[\text{\[u=\frac{(4)\pm\sqrt{(4)^24\times(1)\times(3)}}{2(1)}\]}\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
oh damn my solution is way off \[\sin^2(\arcsin 3) + 4\sin (\arcsin 3) + 3 = 24≠0\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
oh \(u^2+4u+3=0\) NOT \(u^24u+3=0\)
 one year ago

nickhouraneyBest ResponseYou've already chosen the best response.0
but this wasnt the problem that was stated lol
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[u_{1,2}=2\pm1=3,1\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[\sin x=u=3,1\] \[x_{1,2}=\arcsin (1),\quad \arcsin(3)\] \[x_1=\frac \pi2\qquad, x_2=\text{some transcendental nonsense} \] hence\[x=\frac {\pi}2\] CHECKING \[\sin^2x + 4\sin x + 3 = 0\] \[\sin^2\left(\frac\pi 2\right) + 4\sin \left(\frac\pi 2\right) + 3 = 0\]\[1+4(1)+3=0\]\[0=0\]true hence \[\large{x=\frac {\pi}2}\]is the solution to \[\sin^2x + 4\sin x + 3 = 0\]
 one year ago

HeroBest ResponseYou've already chosen the best response.1
People who post questions need to learn how to use the equation editors to avoid such confusion.
 one year ago

panlac01Best ResponseYou've already chosen the best response.0
couldn't agree more @Hero
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
i think someone needs to write a program that can interpet questions and convert them to \(\LaTeX\) automagically
 one year ago

nickhouraneyBest ResponseYou've already chosen the best response.0
@lulu212 i am disappoint at this equation
 one year ago

HeroBest ResponseYou've already chosen the best response.1
I imagine that something like that would have to be interactive. It would have to be some kind of AI that would automatically ask the user something like: Did you mean \(\sin(2x)\) or \(\sin^2(x)\)?
 one year ago

panlac01Best ResponseYou've already chosen the best response.0
beyond OS' capacity :P we can ask Wolfram though. That dude is probably the smartest programmer I've seen alive
 one year ago

HeroBest ResponseYou've already chosen the best response.1
That's because he was reincarnated Einstein
 one year ago

panlac01Best ResponseYou've already chosen the best response.0
hahaha... I think he was already born when Einstein was still alive
 one year ago

HeroBest ResponseYou've already chosen the best response.1
Well, Einstein's lost twin
 one year ago

nickhouraneyBest ResponseYou've already chosen the best response.0
this question has like 40 responses all because of a typing error
 one year ago

HeroBest ResponseYou've already chosen the best response.1
We're still assuming that it is a typing error
 one year ago

HeroBest ResponseYou've already chosen the best response.1
There's no such thing as typing errors. Only human errors.
 one year ago

panlac01Best ResponseYou've already chosen the best response.0
the person who asked for help did not even say anything after the question was posted (TYPOGRAPHICAL ERROR)
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
can't we all be einsteins lost twin?
 one year ago

panlac01Best ResponseYou've already chosen the best response.0
I know that I can't... I have a roach's brain compare to his
 one year ago

nickhouraneyBest ResponseYou've already chosen the best response.0
same difference hero lol
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
twins dont necessarily have the same charistics
 one year ago

panlac01Best ResponseYou've already chosen the best response.0
oh that's right... I'd be the opposite of his intellect then
 one year ago

HeroBest ResponseYou've already chosen the best response.1
In one of Einstein's lost journals, he wrote that his brain was removed as a kid. The person handling his brain accidentally dropped in brain in a toilet, but quietly removed it without telling anyone. Once the brain was placed back into Einstein's head, he felt different, like as if he had more 'powers' and 'ability'. We all know what that led to.
 one year ago
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