At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the **expert** answer you'll need to create a **free** account at **Brainly**

do u know how to solve this ?

sin(2x) is more interesting :)

Is it sin^2x + 4sinx + 3 = 0 ?

Not the answer you are looking for?

Search for more explanations.

|dw:1345778720492:dw|
i dont know why latex is not working..

sin 2x

\[sin2x + 4sinx + 3\]

\[sin2x = 2sinxcosx\]
\[ 2sinxcosx + 4sinx + 3 = 0 \]

have you tried that yet?

hm...hm.... u need...to find the General soln of this....!

I don't understand why @UnkleRhaukus can't finish it

hmm
http://www.wolframalpha.com/input/?i=sin2x+%2B+4sin+x+%2B+3+%3D+0
i dont think its possible..

i think..tthere is mistake in question..))))

I think it should be \(sin^2x + 4sinx +3 =0\)

then \(u=sinx\) more reasonable

then it is a quad eq

we can find sinx

this question can be solved ............why u guys are worrying????????

it cant be solved just endless ways of writing the equation

the equation toolbar in this thing sucks hairy ______. how do you write it so neatly like that?

oh damn
my solution is way off
\[\sin^2(\arcsin 3) + 4\sin (\arcsin 3) + 3 = 24≠0\]

oh
\(u^2+4u+3=0\) NOT \(u^2-4u+3=0\)

but this wasnt the problem that was stated lol

\[u_{1,2}=-2\pm1=-3,-1\]

ta-da

People who post questions need to learn how to use the equation editors to avoid such confusion.

That's because he was reincarnated Einstein

hahaha... I think he was already born when Einstein was still alive

Well, Einstein's lost twin

this question has like 40 responses all because of a typing error

We're still assuming that it is a typing error

it is

There's no such thing as typing errors. Only human errors.

can't we all be einsteins lost twin?

I know that I can't... I have a roach's brain compare to his

same difference hero lol

twins dont necessarily have the same charistics

oh that's right... I'd be the opposite of his intellect then

*
characteristic

oh my.

where's David Hume?

Not the answer you are looking for?

Search for more explanations.