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|dw:1345779977023:dw|

i am stuck from there

i did it a different way...

well explain.

with integrals...

well. it shouldn't be that complicated im only doing geometry.

I think I meant to post the area of a sector of a circle

you guys are thinking too hard its only like subtracting a sector

Area of sector - area of triangle

Yeah that

here ill take it a bit further.
|dw:1345780578744:dw|
does that help?

It will not be hard to find \(r\)

Is the vertex of angle 120 is the center of the circle?

yep

|dw:1345780720301:dw|
looks like you can use the sine rule..

lets find \(r\) first

|dw:1345780842471:dw|

I got 8 as well using the sine rule

Now its easy..you can do it yourself

ok so 64 pi is the area of the circle

and the area of the triangle left side is 1/2 * 4sqroot3 * 4

*2 to make up for the other side.

ok

and it must be in radians..so convert it..

oh heck nah jose

you guys are thinking too hard o.0

1/2 4sqrt3 * 4 or
8sqrt3 * 2 for the other side

|dw:1345781211630:dw|
|dw:1345781273195:dw|

|dw:1345781325118:dw|

so the final answer is \[64\pi/3 - 16\sqrt{3}\]

yes good job @Lethal

yep, i would best response both of u but i can only do one. thx alex.