mandypruitt
I need help solving the following basic linear equation:
13y/5=2



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haganmc
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is 3y or (1 3y) over 5?

mandypruitt
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\[13y \div5=2\]

mandypruitt
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13y over 5 equals 2

haganmc
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12=3y/5,
1*5=3y
5/3=y

mandypruitt
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It says the answers is 3 that is why I am confused

mandypruitt
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I got the same thing as you the first time

haganmc
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(13y)/5=2,
13y=2*5
3y=101,
y=9/3,
y=3

mandypruitt
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@haganmc thank you it makes sense