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manishsatywaliBest ResponseYou've already chosen the best response.0
use cardons method
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
use factorer's method
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
x^2 ( 3x + 1) 5 ( 3x + 1)
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.3
3x^3+x^215x5 (3x^3+x^2)+(15x5) x^2(3x+1)5(3x+1) (x^25)(3x+1)
 one year ago

manishsatywaliBest ResponseYou've already chosen the best response.0
(x^2 5) (3x +1)
 one year ago

AudrianaSBest ResponseYou've already chosen the best response.0
So how would I then completely factor it out in order to get a positive and negative number?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.3
Not sure what you mean, but you could factor \(\Large x^25\) further \[\Large x^25\] \[\Large x^2\left(\sqrt{5} \right )^2\] \[\Large \left(x\sqrt{5} \right )\left(x+\sqrt{5} \right )\] So \[\Large (x^25)(3x+1)\] then becomes \[\Large \left(x\sqrt{5} \right )\left(x+\sqrt{5} \right )(3x+1)\]
 one year ago

AudrianaSBest ResponseYou've already chosen the best response.0
Well, my book has the answer and it saw + 5/2. But I dont know how to get to that
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.3
Is 3x^3+x^215x5 = 0 the original problem?
 one year ago

manishsatywaliBest ResponseYou've already chosen the best response.0
see @AudrianaS dear ..............ans. is 5/2 ,+5/2 and 1/3.. you must know that alternating sign. of solution is the property of cubic eqn.
 one year ago

AudrianaSBest ResponseYou've already chosen the best response.0
@jim_thompson5910 Yes
 one year ago

AudrianaSBest ResponseYou've already chosen the best response.0
@manishsatywali Yeah I know it is 5/2 and +5/2 but I dont know about 1/3. I can see how you got it, but its just not in the book
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.3
There should be 3 solutions and they are x = 1/3, x = sqrt(5), or x = sqrt(5)
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.3
So there's either a typo or something is missing.
 one year ago

AudrianaSBest ResponseYou've already chosen the best response.0
alright then. Thank you all. :)
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.3
I would double check the problem. Notice how you have a cubic equation. So if you have 2 real roots, then you must also have a 3rd real root.
 one year ago

AudrianaSBest ResponseYou've already chosen the best response.0
yesh it just says, factor completely: 3x^3+x^215x5
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.3
Well if you're just factoring over the rationals, then you would stop at (x^25)(3x+1)
 one year ago

AudrianaSBest ResponseYou've already chosen the best response.0
Alright, that makes sense. Thank you.
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.3
you're welcome
 one year ago
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