A community for students.
Here's the question you clicked on:
 0 viewing
AudrianaS
 3 years ago
factor 3x^3+x^215x5
AudrianaS
 3 years ago
factor 3x^3+x^215x5

This Question is Closed

manishsatywali
 3 years ago
Best ResponseYou've already chosen the best response.0use cardons method

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0use factorer's method

Yahoo!
 3 years ago
Best ResponseYou've already chosen the best response.0x^2 ( 3x + 1) 5 ( 3x + 1)

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.33x^3+x^215x5 (3x^3+x^2)+(15x5) x^2(3x+1)5(3x+1) (x^25)(3x+1)

manishsatywali
 3 years ago
Best ResponseYou've already chosen the best response.0(x^2 5) (3x +1)

AudrianaS
 3 years ago
Best ResponseYou've already chosen the best response.0So how would I then completely factor it out in order to get a positive and negative number?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.3Not sure what you mean, but you could factor \(\Large x^25\) further \[\Large x^25\] \[\Large x^2\left(\sqrt{5} \right )^2\] \[\Large \left(x\sqrt{5} \right )\left(x+\sqrt{5} \right )\] So \[\Large (x^25)(3x+1)\] then becomes \[\Large \left(x\sqrt{5} \right )\left(x+\sqrt{5} \right )(3x+1)\]

AudrianaS
 3 years ago
Best ResponseYou've already chosen the best response.0Well, my book has the answer and it saw + 5/2. But I dont know how to get to that

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.3Is 3x^3+x^215x5 = 0 the original problem?

manishsatywali
 3 years ago
Best ResponseYou've already chosen the best response.0see @AudrianaS dear ..............ans. is 5/2 ,+5/2 and 1/3.. you must know that alternating sign. of solution is the property of cubic eqn.

AudrianaS
 3 years ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 Yes

AudrianaS
 3 years ago
Best ResponseYou've already chosen the best response.0@manishsatywali Yeah I know it is 5/2 and +5/2 but I dont know about 1/3. I can see how you got it, but its just not in the book

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.3There should be 3 solutions and they are x = 1/3, x = sqrt(5), or x = sqrt(5)

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.3So there's either a typo or something is missing.

AudrianaS
 3 years ago
Best ResponseYou've already chosen the best response.0alright then. Thank you all. :)

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.3I would double check the problem. Notice how you have a cubic equation. So if you have 2 real roots, then you must also have a 3rd real root.

AudrianaS
 3 years ago
Best ResponseYou've already chosen the best response.0yesh it just says, factor completely: 3x^3+x^215x5

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.3Well if you're just factoring over the rationals, then you would stop at (x^25)(3x+1)

AudrianaS
 3 years ago
Best ResponseYou've already chosen the best response.0Alright, that makes sense. Thank you.

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.3you're welcome
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.