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manishsatywali Group TitleBest ResponseYou've already chosen the best response.0
use cardons method
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
use factorer's method
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
x^2 ( 3x + 1) 5 ( 3x + 1)
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.3
3x^3+x^215x5 (3x^3+x^2)+(15x5) x^2(3x+1)5(3x+1) (x^25)(3x+1)
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
(3x +1) (x^2  5)
 2 years ago

manishsatywali Group TitleBest ResponseYou've already chosen the best response.0
(x^2 5) (3x +1)
 2 years ago

AudrianaS Group TitleBest ResponseYou've already chosen the best response.0
So how would I then completely factor it out in order to get a positive and negative number?
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.3
Not sure what you mean, but you could factor \(\Large x^25\) further \[\Large x^25\] \[\Large x^2\left(\sqrt{5} \right )^2\] \[\Large \left(x\sqrt{5} \right )\left(x+\sqrt{5} \right )\] So \[\Large (x^25)(3x+1)\] then becomes \[\Large \left(x\sqrt{5} \right )\left(x+\sqrt{5} \right )(3x+1)\]
 2 years ago

AudrianaS Group TitleBest ResponseYou've already chosen the best response.0
Well, my book has the answer and it saw + 5/2. But I dont know how to get to that
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.3
Is 3x^3+x^215x5 = 0 the original problem?
 2 years ago

manishsatywali Group TitleBest ResponseYou've already chosen the best response.0
see @AudrianaS dear ..............ans. is 5/2 ,+5/2 and 1/3.. you must know that alternating sign. of solution is the property of cubic eqn.
 2 years ago

AudrianaS Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910 Yes
 2 years ago

AudrianaS Group TitleBest ResponseYou've already chosen the best response.0
@manishsatywali Yeah I know it is 5/2 and +5/2 but I dont know about 1/3. I can see how you got it, but its just not in the book
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.3
There should be 3 solutions and they are x = 1/3, x = sqrt(5), or x = sqrt(5)
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.3
So there's either a typo or something is missing.
 2 years ago

AudrianaS Group TitleBest ResponseYou've already chosen the best response.0
alright then. Thank you all. :)
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.3
I would double check the problem. Notice how you have a cubic equation. So if you have 2 real roots, then you must also have a 3rd real root.
 2 years ago

AudrianaS Group TitleBest ResponseYou've already chosen the best response.0
yesh it just says, factor completely: 3x^3+x^215x5
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.3
Well if you're just factoring over the rationals, then you would stop at (x^25)(3x+1)
 2 years ago

AudrianaS Group TitleBest ResponseYou've already chosen the best response.0
Alright, that makes sense. Thank you.
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.3
you're welcome
 2 years ago
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