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x= [17/2]^1/2 +5|dw:1345790422320:dw|

x-intercepts? this is an equation in one variable....
how do you do that?

http://finedrafts.com/files/Larson%20PreCal%208th/Larson%20Precal%20CH2.pdf

Am I suppose to distribute the 2?

I'm always late....

oh okay thank you that makes so much sense :)

Wow. That's complicated. I thought all I had to do was to solve it but seems not :(

this is a function:
y = 2(x-5)^2
this is not a function:
17 = 2(x-5)^2

parabolas always have 2 x-intercepts unless k=0, is it not?

But how to get the x-intercept(s)???
There is no y...

Think the x-intercept is 8.5,0

dpalnc solved it,
x=5 - sqrt(17/2)
x=5+ sqrt(17/2)

Eh?! Then, for 17=x+3, the x-intercept is 17-3 = 14?!

you have been trolled

LOL

a vertical line that curves...obviously troll ^^

^trOWL

yeah buwahhahahahaha

ang troll ^^^

this is not a function

no. this is just not a function. nothing more; nothing less

it's a relation, but not a function

x-intercepts occur in function only

when did i say it is a function?

I said it was, my mistake

you were saying it had an x-intercept

two values for x...

it has values for x...but no x-intercept

but the vertical line intercepts the x-axis...

yes. LG you are right

like i said. you got trolled

cross or touches...

so are you saying that a circle (which is a curve) does not have x-intercepts?

yes it doesnt. it's not a function

circle is not a function

neither do ellipses

function = 1 to 1 value

so why can't you call the where a vertical line crosses the the x-axis the x-intercept?

any closed figure is not a function. it is a plane

this is going beyond the problem now...
bottom line: x has two values

i agree to agree... if that makes sense....

hey LG... i thnk u scared off the asker....
or he/she got bored...

did she ask the problem to be graphed?

lol jk. let us just leave it

yes.... let's graph it....

sorry man... i just miss talkin to LG....

u know u'd make a great ambassador for keeping the peace....:)

so peace to everyone.....:)

I'd be damned...

lol...