Find the x-intercepts: 2(x-5)^2=17

- anonymous

Find the x-intercepts: 2(x-5)^2=17

- Stacey Warren - Expert brainly.com

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- anonymous

x= [17/2]^1/2 +5|dw:1345790422320:dw|

- anonymous

x-intercepts? this is an equation in one variable.... how do you do that?

- anonymous

http://finedrafts.com/files/Larson%20PreCal%208th/Larson%20Precal%20CH2.pdf

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## More answers

- anonymous

Am I suppose to distribute the 2?

- anonymous

ahh.... my bad.... because this is an equation in one variable, it is just a vertical line.... so solving for x will give you the only x-intercept....

- anonymous

since this is a quadratic function, you will get 2 values for the x-intercepts. read pp 126-129 in the link I've posted above.

- anonymous

2 x-intercepts? \[2(x-5)^2=17\]Divide both sides by 2\[(x-5)^2=\frac{17}{2}\]Take square roots for both sides \[(x-5)=\pm \frac{17}{2}\]Add 5 to both sides to get the answer.

- anonymous

I'm always late....

- anonymous

oh okay thank you that makes so much sense :)

- anonymous

hold on folks... this is an equation in x only.... this is a vertical line.... and not a function.... "Find the x-intercepts: 2(x-5)^2=17"

- anonymous

Wow. That's complicated. I thought all I had to do was to solve it but seems not :(

- anonymous

this is a function: y = 2(x-5)^2 this is not a function: 17 = 2(x-5)^2

- anonymous

parabolas always have 2 x-intercepts unless k=0, is it not?

- anonymous

But how to get the x-intercept(s)??? There is no y...

- anonymous

in any function, to find the x-intercepts, set y=0 and solve.... how are you gonna set y=0 in the equation 2(x-5)^2 =17 ????

- razor99

Think the x-intercept is 8.5,0

- anonymous

Perhaps this would be the case? y = 2(x-5)^2-17 Put y=0 2(x-5)^2-17 = 0 2(x-5)^2=17 . . . Solve x to find the x-intercepts. Hmm...

- anonymous

dpalnc solved it, x=5 - sqrt(17/2) x=5+ sqrt(17/2)

- anonymous

compare these two equations: y = x + 3 and 17 = x + 3 that first one is a line and you can find the x-intercept by setting y=0 then solving 0 = x + 3. but that second equation is just a vertical line....

- anonymous

Eh?! Then, for 17=x+3, the x-intercept is 17-3 = 14?!

- lgbasallote

you have been trolled

- anonymous

dang this chrome browser.... x = 14 is a vertical line and that's where it crosses the x-axis.... but back to the problem... did i say 1 x-intercept? i mean two as panlac says.... :)

- anonymous

LOL

- lgbasallote

a vertical line that curves...obviously troll ^^

- anonymous

how 'bout two vertical lines... it's implied when u solve a quadratic you have to consider the positive and negative square root....

- lgbasallote

^trOWL

- anonymous

yeah buwahhahahahaha

- anonymous

ang troll ^^^

- lgbasallote

this goes against the teachings of the monks... the forefathers defined x-intercept as "the value of y when x is 0" however, there is no y....

- lgbasallote

this is not a function

- anonymous

right... so when you solve for x in that equation, you get two vertical lines... an equation in only 1 variable x is not a function...

- lgbasallote

no. this is just not a function. nothing more; nothing less

- lgbasallote

it's a relation, but not a function

- lgbasallote

x-intercepts occur in function only

- anonymous

when did i say it is a function?

- anonymous

I said it was, my mistake

- lgbasallote

you were saying it had an x-intercept

- anonymous

two values for x...

- lgbasallote

it has values for x...but no x-intercept

- anonymous

but the vertical line intercepts the x-axis...

- anonymous

yes. LG you are right

- lgbasallote

http://mathworld.wolfram.com/x-Intercept.html "The point at which a curve or FUNCTION crosses the x-axis (i.e., when in two dimensions)."

- lgbasallote

like i said. you got trolled

- anonymous

cross or touches...

- anonymous

so are you saying that a circle (which is a curve) does not have x-intercepts?

- lgbasallote

yes it doesnt. it's not a function

- anonymous

circle is not a function

- lgbasallote

neither do ellipses

- anonymous

function = 1 to 1 value

- anonymous

so why can't you call the where a vertical line crosses the the x-axis the x-intercept?

- lgbasallote

any closed figure is not a function. it is a plane

- anonymous

this is going beyond the problem now... bottom line: x has two values

- anonymous

i agree to agree... if that makes sense....

- anonymous

hey LG... i thnk u scared off the asker.... or he/she got bored...

- anonymous

did she ask the problem to be graphed?

- anonymous

lol jk. let us just leave it

- lgbasallote

i would like to quote myself "you got trolled" relations have x-intercepts too http://en.wikibooks.org/wiki/Algebra/Intercepts

- anonymous

yes.... let's graph it....

- anonymous

this is really going beyond now... why can't we agree that the intercepts are where either the vertical line or horizontal line are touched or crossed? did I start the fire when I said it was a function? I retracted it so OS can be a better place for students once again...

- anonymous

sorry man... i just miss talkin to LG....

- anonymous

u know u'd make a great ambassador for keeping the peace....:)

- anonymous

so peace to everyone.....:)

- anonymous

I'd be damned...

- anonymous

lol...

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