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AudrianaS

  • 2 years ago

Find the x-intercepts: 2(x-5)^2=17

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  1. manishsatywali
    • 2 years ago
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    x= [17/2]^1/2 +5|dw:1345790422320:dw|

  2. dpaInc
    • 2 years ago
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    x-intercepts? this is an equation in one variable.... how do you do that?

  3. panlac01
    • 2 years ago
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    http://finedrafts.com/files/Larson%20PreCal%208th/Larson%20Precal%20CH2.pdf

  4. AudrianaS
    • 2 years ago
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    Am I suppose to distribute the 2?

  5. dpaInc
    • 2 years ago
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    ahh.... my bad.... because this is an equation in one variable, it is just a vertical line.... so solving for x will give you the only x-intercept....

  6. panlac01
    • 2 years ago
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    since this is a quadratic function, you will get 2 values for the x-intercepts. read pp 126-129 in the link I've posted above.

  7. RolyPoly
    • 2 years ago
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    2 x-intercepts? \[2(x-5)^2=17\]Divide both sides by 2\[(x-5)^2=\frac{17}{2}\]Take square roots for both sides \[(x-5)=\pm \frac{17}{2}\]Add 5 to both sides to get the answer.

  8. RolyPoly
    • 2 years ago
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    I'm always late....

  9. AudrianaS
    • 2 years ago
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    oh okay thank you that makes so much sense :)

  10. dpaInc
    • 2 years ago
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    hold on folks... this is an equation in x only.... this is a vertical line.... and not a function.... "Find the x-intercepts: 2(x-5)^2=17"

  11. RolyPoly
    • 2 years ago
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    Wow. That's complicated. I thought all I had to do was to solve it but seems not :(

  12. dpaInc
    • 2 years ago
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    this is a function: y = 2(x-5)^2 this is not a function: 17 = 2(x-5)^2

  13. panlac01
    • 2 years ago
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    parabolas always have 2 x-intercepts unless k=0, is it not?

  14. RolyPoly
    • 2 years ago
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    But how to get the x-intercept(s)??? There is no y...

  15. dpaInc
    • 2 years ago
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    in any function, to find the x-intercepts, set y=0 and solve.... how are you gonna set y=0 in the equation 2(x-5)^2 =17 ????

  16. razor99
    • 2 years ago
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    Think the x-intercept is 8.5,0

  17. RolyPoly
    • 2 years ago
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    Perhaps this would be the case? y = 2(x-5)^2-17 Put y=0 2(x-5)^2-17 = 0 2(x-5)^2=17 . . . Solve x to find the x-intercepts. Hmm...

  18. panlac01
    • 2 years ago
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    dpalnc solved it, x=5 - sqrt(17/2) x=5+ sqrt(17/2)

  19. dpaInc
    • 2 years ago
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    compare these two equations: y = x + 3 and 17 = x + 3 that first one is a line and you can find the x-intercept by setting y=0 then solving 0 = x + 3. but that second equation is just a vertical line....

  20. RolyPoly
    • 2 years ago
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    Eh?! Then, for 17=x+3, the x-intercept is 17-3 = 14?!

  21. lgbasallote
    • 2 years ago
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    you have been trolled

  22. dpaInc
    • 2 years ago
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    dang this chrome browser.... x = 14 is a vertical line and that's where it crosses the x-axis.... but back to the problem... did i say 1 x-intercept? i mean two as panlac says.... :)

  23. panlac01
    • 2 years ago
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    LOL

  24. lgbasallote
    • 2 years ago
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    a vertical line that curves...obviously troll ^^

  25. dpaInc
    • 2 years ago
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    how 'bout two vertical lines... it's implied when u solve a quadratic you have to consider the positive and negative square root....

  26. lgbasallote
    • 2 years ago
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    ^trOWL

  27. dpaInc
    • 2 years ago
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    yeah buwahhahahahaha

  28. dpaInc
    • 2 years ago
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    ang troll ^^^

  29. lgbasallote
    • 2 years ago
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    this goes against the teachings of the monks... the forefathers defined x-intercept as "the value of y when x is 0" however, there is no y....

  30. lgbasallote
    • 2 years ago
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    this is not a function

  31. dpaInc
    • 2 years ago
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    right... so when you solve for x in that equation, you get two vertical lines... an equation in only 1 variable x is not a function...

  32. lgbasallote
    • 2 years ago
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    no. this is just not a function. nothing more; nothing less

  33. lgbasallote
    • 2 years ago
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    it's a relation, but not a function

  34. lgbasallote
    • 2 years ago
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    x-intercepts occur in function only

  35. dpaInc
    • 2 years ago
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    when did i say it is a function?

  36. panlac01
    • 2 years ago
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    I said it was, my mistake

  37. lgbasallote
    • 2 years ago
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    you were saying it had an x-intercept

  38. panlac01
    • 2 years ago
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    two values for x...

  39. lgbasallote
    • 2 years ago
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    it has values for x...but no x-intercept

  40. dpaInc
    • 2 years ago
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    but the vertical line intercepts the x-axis...

  41. panlac01
    • 2 years ago
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    yes. LG you are right

  42. lgbasallote
    • 2 years ago
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    http://mathworld.wolfram.com/x-Intercept.html "The point at which a curve or FUNCTION crosses the x-axis (i.e., when in two dimensions)."

  43. lgbasallote
    • 2 years ago
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    like i said. you got trolled

  44. panlac01
    • 2 years ago
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    cross or touches...

  45. dpaInc
    • 2 years ago
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    so are you saying that a circle (which is a curve) does not have x-intercepts?

  46. lgbasallote
    • 2 years ago
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    yes it doesnt. it's not a function

  47. panlac01
    • 2 years ago
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    circle is not a function

  48. lgbasallote
    • 2 years ago
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    neither do ellipses

  49. panlac01
    • 2 years ago
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    function = 1 to 1 value

  50. dpaInc
    • 2 years ago
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    so why can't you call the where a vertical line crosses the the x-axis the x-intercept?

  51. lgbasallote
    • 2 years ago
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    any closed figure is not a function. it is a plane

  52. panlac01
    • 2 years ago
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    this is going beyond the problem now... bottom line: x has two values

  53. dpaInc
    • 2 years ago
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    i agree to agree... if that makes sense....

  54. dpaInc
    • 2 years ago
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    hey LG... i thnk u scared off the asker.... or he/she got bored...

  55. panlac01
    • 2 years ago
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    did she ask the problem to be graphed?

  56. panlac01
    • 2 years ago
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    lol jk. let us just leave it

  57. lgbasallote
    • 2 years ago
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    i would like to quote myself "you got trolled" relations have x-intercepts too http://en.wikibooks.org/wiki/Algebra/Intercepts

  58. dpaInc
    • 2 years ago
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    yes.... let's graph it....

  59. panlac01
    • 2 years ago
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    this is really going beyond now... why can't we agree that the intercepts are where either the vertical line or horizontal line are touched or crossed? did I start the fire when I said it was a function? I retracted it so OS can be a better place for students once again...

  60. dpaInc
    • 2 years ago
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    sorry man... i just miss talkin to LG....

  61. dpaInc
    • 2 years ago
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    u know u'd make a great ambassador for keeping the peace....:)

  62. dpaInc
    • 2 years ago
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    so peace to everyone.....:)

  63. panlac01
    • 2 years ago
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    I'd be damned...

  64. dpaInc
    • 2 years ago
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    lol...

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