anonymous
  • anonymous
In 1987, the Australian humpback whale population was 350 and has increased at a rate of about 14% each year since then. Write a function to model population growth. Use a graph to predict when the population will reach 20, 000.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Use the compound interest formula you used in the other question.
anonymous
  • anonymous
sooo wud it b 350(1+1.014)=20000
anonymous
  • anonymous
Almost, the graph you will draw is 350(1+0.014)^n. Then you will go to the point where the graph equals 20,000 and see how many years it has been.

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anonymous
  • anonymous
290.9?
anonymous
  • anonymous
290.99 is the correct answer, did you solve it using the graph?
anonymous
  • anonymous
no im not sure how 2 graph it
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=350%281.014%29^n+from+-1+to+300
anonymous
  • anonymous
a)P(t) = 350(1.14)t; the population will reach 20,000 in about 30.9 yr. b)P(t) = 350(0.86)t; the population will reach 20,000 in about 19.5 yr. c)P(t) = 350(0.86)t; the population will reach 20,000 in about 39.1 yr.wwwwww d)P(t) = 350(1.14)t; the population will reach 20,000 in about 25.6 yr.
anonymous
  • anonymous
Sorry, 290.99 is not the correct answer at all. The interest is 14% (which is 1.14), not 1.4% (which is 1.014). If you put 1.14 into the formula instead of 1.014 you should get the correct answer. Let me know how it goes.
anonymous
  • anonymous
wud it b A?
anonymous
  • anonymous
30.8?
anonymous
  • anonymous
The answer on my calculator is 30.87543347. The correct rounding of this to one decimal place is 30.9. So the answer is A.

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