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JamenS

A motor scooter purchased for $1,000 depreciates at an annual rate of 15%. Write an exponential function, and graph the function. Use the graph to predict when the value will fall below $100.

  • one year ago
  • one year ago

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  1. Traxter
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    You must be able to start this one off for yourself. Can you show us what you have so far?

    • one year ago
  2. JamenS
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    1000(1.15)=100?

    • one year ago
  3. hal_stirrup
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    hi

    • one year ago
  4. JamenS
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    hi

    • one year ago
  5. JamenS
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    can u help me :)

    • one year ago
  6. hal_stirrup
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    ok ask you self . what is the value of motor scooter after 1 year?

    • one year ago
  7. JamenS
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    150$....

    • one year ago
  8. JamenS
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    ?

    • one year ago
  9. hal_stirrup
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    no

    • one year ago
  10. hal_stirrup
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    so what the question is really saying is , the value of motor scooter goes down by 15%.

    • one year ago
  11. SNSDYoona
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    100 = 1000e^(-0.15t)

    • one year ago
  12. JamenS
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    850$

    • one year ago
  13. hal_stirrup
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    @SNSDYoona we dont give answers out like that.

    • one year ago
  14. SNSDYoona
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    1000 = the starting money that u purchased it the basic formula for this exponential decay and growth functions is A= Ye^(kt)

    • one year ago
  15. SNSDYoona
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    thts why i give him the answer first to see if he does any calculation wrong then explain to him if he doesnt get it

    • one year ago
  16. hal_stirrup
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    thats why we don't give answers out. you need to explain the exponential formula. Not just stated it!!!

    • one year ago
  17. SNSDYoona
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    A = the amount u left after a certain period of time Y = initial amount started with k = ur rate of decay/growth t= the time

    • one year ago
  18. JamenS
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    0.1=(-0.15t)

    • one year ago
  19. JamenS
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    ?

    • one year ago
  20. SNSDYoona
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    have u learn natural logs?

    • one year ago
  21. SNSDYoona
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    from 100 = 1000e^(-0.15t) u simplify it then u get down to 0.1= e^(-0.15t) then u take the natural logs off both side u get ln(0.1) = -0.15t then u solve for t ln(0.1)/0.15 = t

    • one year ago
  22. JamenS
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    i got 0.666

    • one year ago
  23. SNSDYoona
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    u shud get 15.35

    • one year ago
  24. SNSDYoona
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    use ur calculator.. did u type in correctly?

    • one year ago
  25. JamenS
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    i divide .1 by .15?

    • one year ago
  26. SNSDYoona
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    nonono u use ln << ln = natural log

    • one year ago
  27. SNSDYoona
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    look at ur calculator and search for ln

    • one year ago
  28. SNSDYoona
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    press ln and then (0.1)

    • one year ago
  29. SNSDYoona
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    then divide by (-0.15)

    • one year ago
  30. JamenS
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    im using google calculator i dont have 1

    • one year ago
  31. JamenS
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    15.3?

    • one year ago
  32. SNSDYoona
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    yeap

    • one year ago
  33. JamenS
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    v(t) = 0.85(1000)t; the value will fall below $100 in about 18 yr. v(t) = 1000(0.85)t; the value will fall below $100 in about 18 yr. v(t) = 0.85(1000)t; the value will fall below $100 in about 14.2 yr. v(t) = 1000(0.85)t; the value will fall below $100 in about 14.2 yr.

    • one year ago
  34. JamenS
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    u still there

    • one year ago
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