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anonymous
 3 years ago
A motor scooter purchased for $1,000 depreciates at an annual rate of 15%. Write an exponential function, and graph the function. Use the graph to predict when the value will fall below $100.
anonymous
 3 years ago
A motor scooter purchased for $1,000 depreciates at an annual rate of 15%. Write an exponential function, and graph the function. Use the graph to predict when the value will fall below $100.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You must be able to start this one off for yourself. Can you show us what you have so far?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok ask you self . what is the value of motor scooter after 1 year?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so what the question is really saying is , the value of motor scooter goes down by 15%.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@SNSDYoona we dont give answers out like that.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.01000 = the starting money that u purchased it the basic formula for this exponential decay and growth functions is A= Ye^(kt)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thts why i give him the answer first to see if he does any calculation wrong then explain to him if he doesnt get it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thats why we don't give answers out. you need to explain the exponential formula. Not just stated it!!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0A = the amount u left after a certain period of time Y = initial amount started with k = ur rate of decay/growth t= the time

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0have u learn natural logs?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0from 100 = 1000e^(0.15t) u simplify it then u get down to 0.1= e^(0.15t) then u take the natural logs off both side u get ln(0.1) = 0.15t then u solve for t ln(0.1)/0.15 = t

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0use ur calculator.. did u type in correctly?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0nonono u use ln << ln = natural log

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0look at ur calculator and search for ln

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0press ln and then (0.1)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then divide by (0.15)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im using google calculator i dont have 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0v(t) = 0.85(1000)t; the value will fall below $100 in about 18 yr. v(t) = 1000(0.85)t; the value will fall below $100 in about 18 yr. v(t) = 0.85(1000)t; the value will fall below $100 in about 14.2 yr. v(t) = 1000(0.85)t; the value will fall below $100 in about 14.2 yr.
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