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JamenS
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A motor scooter purchased for $1,000 depreciates at an annual rate of 15%. Write an exponential function, and graph the function. Use the graph to predict when the value will fall below $100.
 2 years ago
 2 years ago
JamenS Group Title
A motor scooter purchased for $1,000 depreciates at an annual rate of 15%. Write an exponential function, and graph the function. Use the graph to predict when the value will fall below $100.
 2 years ago
 2 years ago

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Traxter Group TitleBest ResponseYou've already chosen the best response.0
You must be able to start this one off for yourself. Can you show us what you have so far?
 2 years ago

JamenS Group TitleBest ResponseYou've already chosen the best response.1
1000(1.15)=100?
 2 years ago

JamenS Group TitleBest ResponseYou've already chosen the best response.1
can u help me :)
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.0
ok ask you self . what is the value of motor scooter after 1 year?
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.0
so what the question is really saying is , the value of motor scooter goes down by 15%.
 2 years ago

SNSDYoona Group TitleBest ResponseYou've already chosen the best response.0
100 = 1000e^(0.15t)
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.0
@SNSDYoona we dont give answers out like that.
 2 years ago

SNSDYoona Group TitleBest ResponseYou've already chosen the best response.0
1000 = the starting money that u purchased it the basic formula for this exponential decay and growth functions is A= Ye^(kt)
 2 years ago

SNSDYoona Group TitleBest ResponseYou've already chosen the best response.0
thts why i give him the answer first to see if he does any calculation wrong then explain to him if he doesnt get it
 2 years ago

hal_stirrup Group TitleBest ResponseYou've already chosen the best response.0
thats why we don't give answers out. you need to explain the exponential formula. Not just stated it!!!
 2 years ago

SNSDYoona Group TitleBest ResponseYou've already chosen the best response.0
A = the amount u left after a certain period of time Y = initial amount started with k = ur rate of decay/growth t= the time
 2 years ago

JamenS Group TitleBest ResponseYou've already chosen the best response.1
0.1=(0.15t)
 2 years ago

SNSDYoona Group TitleBest ResponseYou've already chosen the best response.0
have u learn natural logs?
 2 years ago

SNSDYoona Group TitleBest ResponseYou've already chosen the best response.0
from 100 = 1000e^(0.15t) u simplify it then u get down to 0.1= e^(0.15t) then u take the natural logs off both side u get ln(0.1) = 0.15t then u solve for t ln(0.1)/0.15 = t
 2 years ago

SNSDYoona Group TitleBest ResponseYou've already chosen the best response.0
u shud get 15.35
 2 years ago

SNSDYoona Group TitleBest ResponseYou've already chosen the best response.0
use ur calculator.. did u type in correctly?
 2 years ago

JamenS Group TitleBest ResponseYou've already chosen the best response.1
i divide .1 by .15?
 2 years ago

SNSDYoona Group TitleBest ResponseYou've already chosen the best response.0
nonono u use ln << ln = natural log
 2 years ago

SNSDYoona Group TitleBest ResponseYou've already chosen the best response.0
look at ur calculator and search for ln
 2 years ago

SNSDYoona Group TitleBest ResponseYou've already chosen the best response.0
press ln and then (0.1)
 2 years ago

SNSDYoona Group TitleBest ResponseYou've already chosen the best response.0
then divide by (0.15)
 2 years ago

JamenS Group TitleBest ResponseYou've already chosen the best response.1
im using google calculator i dont have 1
 2 years ago

JamenS Group TitleBest ResponseYou've already chosen the best response.1
v(t) = 0.85(1000)t; the value will fall below $100 in about 18 yr. v(t) = 1000(0.85)t; the value will fall below $100 in about 18 yr. v(t) = 0.85(1000)t; the value will fall below $100 in about 14.2 yr. v(t) = 1000(0.85)t; the value will fall below $100 in about 14.2 yr.
 2 years ago

JamenS Group TitleBest ResponseYou've already chosen the best response.1
u still there
 2 years ago
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