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JamenS

  • 3 years ago

A motor scooter purchased for $1,000 depreciates at an annual rate of 15%. Write an exponential function, and graph the function. Use the graph to predict when the value will fall below $100.

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  1. Traxter
    • 3 years ago
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    You must be able to start this one off for yourself. Can you show us what you have so far?

  2. JamenS
    • 3 years ago
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    1000(1.15)=100?

  3. hal_stirrup
    • 3 years ago
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    hi

  4. JamenS
    • 3 years ago
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    hi

  5. JamenS
    • 3 years ago
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    can u help me :)

  6. hal_stirrup
    • 3 years ago
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    ok ask you self . what is the value of motor scooter after 1 year?

  7. JamenS
    • 3 years ago
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    150$....

  8. JamenS
    • 3 years ago
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    ?

  9. hal_stirrup
    • 3 years ago
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    no

  10. hal_stirrup
    • 3 years ago
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    so what the question is really saying is , the value of motor scooter goes down by 15%.

  11. SNSDYoona
    • 3 years ago
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    100 = 1000e^(-0.15t)

  12. JamenS
    • 3 years ago
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    850$

  13. hal_stirrup
    • 3 years ago
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    @SNSDYoona we dont give answers out like that.

  14. SNSDYoona
    • 3 years ago
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    1000 = the starting money that u purchased it the basic formula for this exponential decay and growth functions is A= Ye^(kt)

  15. SNSDYoona
    • 3 years ago
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    thts why i give him the answer first to see if he does any calculation wrong then explain to him if he doesnt get it

  16. hal_stirrup
    • 3 years ago
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    thats why we don't give answers out. you need to explain the exponential formula. Not just stated it!!!

  17. SNSDYoona
    • 3 years ago
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    A = the amount u left after a certain period of time Y = initial amount started with k = ur rate of decay/growth t= the time

  18. JamenS
    • 3 years ago
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    0.1=(-0.15t)

  19. JamenS
    • 3 years ago
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    ?

  20. SNSDYoona
    • 3 years ago
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    have u learn natural logs?

  21. SNSDYoona
    • 3 years ago
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    from 100 = 1000e^(-0.15t) u simplify it then u get down to 0.1= e^(-0.15t) then u take the natural logs off both side u get ln(0.1) = -0.15t then u solve for t ln(0.1)/0.15 = t

  22. JamenS
    • 3 years ago
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    i got 0.666

  23. SNSDYoona
    • 3 years ago
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    u shud get 15.35

  24. SNSDYoona
    • 3 years ago
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    use ur calculator.. did u type in correctly?

  25. JamenS
    • 3 years ago
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    i divide .1 by .15?

  26. SNSDYoona
    • 3 years ago
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    nonono u use ln << ln = natural log

  27. SNSDYoona
    • 3 years ago
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    look at ur calculator and search for ln

  28. SNSDYoona
    • 3 years ago
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    press ln and then (0.1)

  29. SNSDYoona
    • 3 years ago
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    then divide by (-0.15)

  30. JamenS
    • 3 years ago
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    im using google calculator i dont have 1

  31. JamenS
    • 3 years ago
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    15.3?

  32. SNSDYoona
    • 3 years ago
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    yeap

  33. JamenS
    • 3 years ago
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    v(t) = 0.85(1000)t; the value will fall below $100 in about 18 yr. v(t) = 1000(0.85)t; the value will fall below $100 in about 18 yr. v(t) = 0.85(1000)t; the value will fall below $100 in about 14.2 yr. v(t) = 1000(0.85)t; the value will fall below $100 in about 14.2 yr.

  34. JamenS
    • 3 years ago
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    u still there

  35. cnn1999
    • one year ago
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    hi

  36. LiamMcBay
    • 6 months ago
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    hi

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