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A motor scooter purchased for $1,000 depreciates at an annual rate of 15%. Write an exponential function, and graph the function. Use the graph to predict when the value will fall below $100.
 one year ago
 one year ago
A motor scooter purchased for $1,000 depreciates at an annual rate of 15%. Write an exponential function, and graph the function. Use the graph to predict when the value will fall below $100.
 one year ago
 one year ago

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TraxterBest ResponseYou've already chosen the best response.0
You must be able to start this one off for yourself. Can you show us what you have so far?
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
ok ask you self . what is the value of motor scooter after 1 year?
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
so what the question is really saying is , the value of motor scooter goes down by 15%.
 one year ago

SNSDYoonaBest ResponseYou've already chosen the best response.0
100 = 1000e^(0.15t)
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
@SNSDYoona we dont give answers out like that.
 one year ago

SNSDYoonaBest ResponseYou've already chosen the best response.0
1000 = the starting money that u purchased it the basic formula for this exponential decay and growth functions is A= Ye^(kt)
 one year ago

SNSDYoonaBest ResponseYou've already chosen the best response.0
thts why i give him the answer first to see if he does any calculation wrong then explain to him if he doesnt get it
 one year ago

hal_stirrupBest ResponseYou've already chosen the best response.0
thats why we don't give answers out. you need to explain the exponential formula. Not just stated it!!!
 one year ago

SNSDYoonaBest ResponseYou've already chosen the best response.0
A = the amount u left after a certain period of time Y = initial amount started with k = ur rate of decay/growth t= the time
 one year ago

SNSDYoonaBest ResponseYou've already chosen the best response.0
have u learn natural logs?
 one year ago

SNSDYoonaBest ResponseYou've already chosen the best response.0
from 100 = 1000e^(0.15t) u simplify it then u get down to 0.1= e^(0.15t) then u take the natural logs off both side u get ln(0.1) = 0.15t then u solve for t ln(0.1)/0.15 = t
 one year ago

SNSDYoonaBest ResponseYou've already chosen the best response.0
use ur calculator.. did u type in correctly?
 one year ago

SNSDYoonaBest ResponseYou've already chosen the best response.0
nonono u use ln << ln = natural log
 one year ago

SNSDYoonaBest ResponseYou've already chosen the best response.0
look at ur calculator and search for ln
 one year ago

SNSDYoonaBest ResponseYou've already chosen the best response.0
press ln and then (0.1)
 one year ago

SNSDYoonaBest ResponseYou've already chosen the best response.0
then divide by (0.15)
 one year ago

JamenSBest ResponseYou've already chosen the best response.0
im using google calculator i dont have 1
 one year ago

JamenSBest ResponseYou've already chosen the best response.0
v(t) = 0.85(1000)t; the value will fall below $100 in about 18 yr. v(t) = 1000(0.85)t; the value will fall below $100 in about 18 yr. v(t) = 0.85(1000)t; the value will fall below $100 in about 14.2 yr. v(t) = 1000(0.85)t; the value will fall below $100 in about 14.2 yr.
 one year ago
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