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nice drawing :P

isnt it finding a value for k????

why do u differentiate the equation ?

|dw:1345805312784:dw|

because i want to see what is the behaviour of function

so i differentiate it to see if there is some critical points like last drawing or not.

so is the answer k=all real numbers?

i think yes...if im not wrong

sorry @Snowflake123 ...

you sub the x back into the y for k i think..

exactly

so whats the k values

why not you try and sub it back in

sub it into y = 2x^2 - 3x^2 - 12x - 7

2x^3**

so the graph will be like this|dw:1345806482815:dw| just try to work it out

why are there two k's?

the equation \(f'(x)\) has 2 roots so there are 2 k's we must work it out

for \(k=k_1,k_2\) there are exactly 2 real roots for the equation \(f(x)=k\)
for \(k_1

so the region we lookin for is \[k>k_2 \ \text{&} \ k

what do u mean by '' there is only one line y=k''

woops forget it i made a mistake; youre right

lol...i hope im right...

yes you are!! i just drew abit it differently so got kinda confused