Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Not sure how to do this: Please explain??? :D Write down the set of values of the constant k for which the equation 2X^3-3X^2-12X-7=k has exactly one real solution. Thanksss

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
nice drawing :P
isnt it finding a value for k????
lol...tnx so for any real number \(k\) there is exactly one solution for the equation see the intersects of horizental lines and \(f(x)\)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

why do u differentiate the equation ?
|dw:1345805312784:dw|
because i want to see what is the behaviour of function
if it was something like this|dw:1345805467267:dw| for some values between \(k_1\) and \(k_2\) there is more than one real root
so i differentiate it to see if there is some critical points like last drawing or not.
so is the answer k=all real numbers?
i think yes...if im not wrong
oops : misread : \[f(x)=2x^3−3x^2−12x−7\]\[f'(x)=6x^2-6x-12=0\]it gives \(x^2-x-2=0\) so \(x=-1,2\) so we have two critical points
sorry @Snowflake123 ...
you sub the x back into the y for k i think..
exactly
so whats the k values
why not you try and sub it back in
sub it into y = 2x^2 - 3x^2 - 12x - 7
2x^3**
so the graph will be like this|dw:1345806482815:dw| just try to work it out
why are there two k's?
the equation \(f'(x)\) has 2 roots so there are 2 k's we must work it out
according to my notes dont you find the roots from the stationary points? so there is only one line \(y=k\)
for \(k=k_1,k_2\) there are exactly 2 real roots for the equation \(f(x)=k\) for \(k_1
so the region we lookin for is \[k>k_2 \ \text{&} \ k
what do u mean by '' there is only one line y=k''
woops forget it i made a mistake; youre right
lol...i hope im right...
yes you are!! i just drew abit it differently so got kinda confused

Not the answer you are looking for?

Search for more explanations.

Ask your own question