## anonymous 4 years ago attach file

1. anonymous

2. anonymous

Not sure but I'm wondering if you have to individually get the limit of each function separately and then plug them in into the equation you are asked for. For example you would add the two limits for the first one

3. anonymous

how?

4. anonymous

for a it says the limit of the function as you approach 1 from the left side.

5. anonymous

for f(x) that would be 3 for g(x) that would be 5 so wouldn't it be 3+5 for a)

6. anonymous

$a) \lim_{x \rightarrow 1^{-}}$

7. anonymous

$1^{-}$write equation than plug x= 1(negative)?

8. anonymous

no that means the limit of x approaches 1 from the left side, Negative means left Positive means right there's a jump discontinuity in x=1 so you will have two values. One different values that you approach from the left and one different from you approach from the right.

9. anonymous

ok,tk

10. anonymous

This is for a) I run through the line starting from the left side and stop when x=1 whatever value i get is the limit for x=1 as it approaches from the left side

11. anonymous

Can I get some feedback @Callisto

12. anonymous

ok

13. anonymous

Understand?

14. anonymous

b,c and d I able do my own,TK

15. anonymous

yes I Understand

16. anonymous

i did feedback

17. experimentX

1) 5 + 3

18. experimentX

2) 4 + 2* 1

19. experimentX

do you get the pattern?

20. anonymous

no

21. experimentX

lim x->1- f(x) + g(x) = (lim x->1- f(x)) + (lim x->1- g(x))

22. experimentX

lim x->1+ f(x) + g(x) = (lim x->1+ f(x)) + (lim x->1+ g(x))

23. anonymous

tk

24. anonymous

I try give you a medal, but don' let me do it

25. experimentX

no probs ... can you do the other problem? lim x->1+ f(x) * g(x) = (lim x->1+ f(x)) * (lim x->1+ g(x))

26. anonymous

c) 3*5=15?

27. experimentX

yep ..

28. anonymous

TK,I have to go

29. experimentX

seeya