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Nancy_Lam
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RyanL.
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Not sure but I'm wondering if you have to individually get the limit of each function separately and then plug them in into the equation you are asked for. For example you would add the two limits for the first one
Nancy_Lam
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how?
RyanL.
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for a it says the limit of the function as you approach 1 from the left side.
RyanL.
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for f(x) that would be 3
for g(x) that would be 5
so wouldn't it be
3+5 for a)
Nancy_Lam
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\[a) \lim_{x \rightarrow 1^{-}}\]
Nancy_Lam
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\[1^{-}\]write equation than plug x= 1(negative)?
RyanL.
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no that means the limit of x approaches 1 from the left side,
Negative means left
Positive means right
there's a jump discontinuity in x=1 so you will have two values. One different values that you approach from the left and one different from you approach from the right.
Nancy_Lam
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ok,tk
RyanL.
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This is for a)
I run through the line starting from the left side and stop when x=1
whatever value i get is the limit for x=1 as it approaches from the left side
RyanL.
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Can I get some feedback @Callisto
Nancy_Lam
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ok
RyanL.
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Understand?
Nancy_Lam
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b,c and d I able do my own,TK
Nancy_Lam
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yes I Understand
Nancy_Lam
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i did feedback
experimentX
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1) 5 + 3
experimentX
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2) 4 + 2* 1
experimentX
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do you get the pattern?
Nancy_Lam
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no
experimentX
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lim x->1- f(x) + g(x) = (lim x->1- f(x)) + (lim x->1- g(x))
experimentX
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lim x->1+ f(x) + g(x) = (lim x->1+ f(x)) + (lim x->1+ g(x))
Nancy_Lam
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tk
Nancy_Lam
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I try give you a medal, but don' let me do it
experimentX
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no probs ... can you do the other problem?
lim x->1+ f(x) * g(x) = (lim x->1+ f(x)) * (lim x->1+ g(x))
Nancy_Lam
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c) 3*5=15?
experimentX
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yep ..
Nancy_Lam
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TK,I have to go
experimentX
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seeya