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A juggler is performing an act by juggling several balls. The juggler throws the balls up at an initial height of 3.9 feet with a speed of 14.8 feet per second. If the juggler did not catch a ball, about how long will it take the ball to hit the floor? 1.45 secs 1.14 secs 0.28 secs 0.21 secs

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Do..u knw kinematics equations of motion
^^that sounds like physics

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Other answers:

V = u + at
um... i thought it was H(t)= -16t^2+vt+s
first we need to convert feet to meter
ok...whats next
then the time it takes to reach the maximum height
wait why do i change it from feet to meters?
because we are going to use a=g=-9.81m/s^2
oh okay
Now, can u?
whats the a and g? sorry
that is accleration
ok.......walk me through
convert 3.9 feet into meter
about one meter?
14.8 feet per second in meter per second?
oh okay 4 meters and something
3.9 feet = 1.18872m and 14.8 feet per second=4.51104 meter per second
now,v=u+at 0=4.51 + (-9.81)t t=0.46seconds
Again, v^2=u^2+2as 0^2=(4.51)^2 + 2(-9.81)s s=1.04 m
So, maximum height = 1.19+1.04 m = 2.23m
Now, s=ut+1/2 at^2 2.23 = 0*t + 1/2 (9.81) t^2 t=0.67 seconds
So, total time = 0.46+0.67 =1.13 seconds
got it?
ohh okay.

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