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kiamonstaa Group Title

A juggler is performing an act by juggling several balls. The juggler throws the balls up at an initial height of 3.9 feet with a speed of 14.8 feet per second. If the juggler did not catch a ball, about how long will it take the ball to hit the floor? 1.45 secs 1.14 secs 0.28 secs 0.21 secs

  • one year ago
  • one year ago

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  1. Yahoo! Group Title
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    Do..u knw kinematics equations of motion

    • one year ago
  2. kiamonstaa Group Title
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    um.....no

    • one year ago
  3. lgbasallote Group Title
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    ^^that sounds like physics

    • one year ago
  4. Yahoo! Group Title
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    V = u + at

    • one year ago
  5. kiamonstaa Group Title
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    um... i thought it was H(t)= -16t^2+vt+s

    • one year ago
  6. sauravshakya Group Title
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    first we need to convert feet to meter

    • one year ago
  7. kiamonstaa Group Title
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    ok...whats next

    • one year ago
  8. sauravshakya Group Title
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    then the time it takes to reach the maximum height

    • one year ago
  9. kiamonstaa Group Title
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    wait why do i change it from feet to meters?

    • one year ago
  10. sauravshakya Group Title
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    because we are going to use a=g=-9.81m/s^2

    • one year ago
  11. kiamonstaa Group Title
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    oh okay

    • one year ago
  12. sauravshakya Group Title
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    Now, can u?

    • one year ago
  13. kiamonstaa Group Title
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    whats the a and g? sorry

    • one year ago
  14. sauravshakya Group Title
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    that is accleration

    • one year ago
  15. kiamonstaa Group Title
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    ok.......walk me through

    • one year ago
  16. sauravshakya Group Title
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    convert 3.9 feet into meter

    • one year ago
  17. kiamonstaa Group Title
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    about one meter?

    • one year ago
  18. sauravshakya Group Title
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    14.8 feet per second in meter per second?

    • one year ago
  19. kiamonstaa Group Title
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    oh okay 4 meters and something

    • one year ago
  20. sauravshakya Group Title
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    3.9 feet = 1.18872m and 14.8 feet per second=4.51104 meter per second

    • one year ago
  21. sauravshakya Group Title
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    now,v=u+at 0=4.51 + (-9.81)t t=0.46seconds

    • one year ago
  22. sauravshakya Group Title
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    Again, v^2=u^2+2as 0^2=(4.51)^2 + 2(-9.81)s s=1.04 m

    • one year ago
  23. sauravshakya Group Title
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    So, maximum height = 1.19+1.04 m = 2.23m

    • one year ago
  24. sauravshakya Group Title
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    Now, s=ut+1/2 at^2 2.23 = 0*t + 1/2 (9.81) t^2 t=0.67 seconds

    • one year ago
  25. sauravshakya Group Title
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    So, total time = 0.46+0.67 =1.13 seconds

    • one year ago
  26. sauravshakya Group Title
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    got it?

    • one year ago
  27. kiamonstaa Group Title
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    ohh okay.

    • one year ago
  28. kiamonstaa Group Title
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    thanks

    • one year ago
  29. sauravshakya Group Title
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    welcome

    • one year ago
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