kiamonstaa
A juggler is performing an act by juggling several balls. The juggler throws the balls up at an initial height of 3.9 feet with a speed of 14.8 feet per second. If the juggler did not catch a ball, about how long will it take the ball to hit the floor?
1.45 secs
1.14 secs
0.28 secs
0.21 secs
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Yahoo!
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Do..u knw kinematics equations of motion
kiamonstaa
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um.....no
lgbasallote
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^^that sounds like physics
Yahoo!
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V = u + at
kiamonstaa
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um... i thought it was H(t)= -16t^2+vt+s
sauravshakya
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first we need to convert feet to meter
kiamonstaa
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ok...whats next
sauravshakya
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then the time it takes to reach the maximum height
kiamonstaa
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wait why do i change it from feet to meters?
sauravshakya
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because we are going to use a=g=-9.81m/s^2
kiamonstaa
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oh okay
sauravshakya
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Now, can u?
kiamonstaa
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whats the a and g?
sorry
sauravshakya
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that is accleration
kiamonstaa
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ok.......walk me through
sauravshakya
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convert 3.9 feet into meter
kiamonstaa
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about one meter?
sauravshakya
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14.8 feet per second in meter per second?
kiamonstaa
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oh okay 4 meters and something
sauravshakya
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3.9 feet = 1.18872m and 14.8 feet per second=4.51104 meter per second
sauravshakya
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now,v=u+at
0=4.51 + (-9.81)t
t=0.46seconds
sauravshakya
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Again, v^2=u^2+2as
0^2=(4.51)^2 + 2(-9.81)s
s=1.04 m
sauravshakya
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So, maximum height = 1.19+1.04 m = 2.23m
sauravshakya
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Now, s=ut+1/2 at^2
2.23 = 0*t + 1/2 (9.81) t^2
t=0.67 seconds
sauravshakya
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So, total time = 0.46+0.67 =1.13 seconds
sauravshakya
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got it?
kiamonstaa
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ohh okay.
kiamonstaa
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thanks
sauravshakya
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welcome