## kiamonstaa 3 years ago A juggler is performing an act by juggling several balls. The juggler throws the balls up at an initial height of 3.9 feet with a speed of 14.8 feet per second. If the juggler did not catch a ball, about how long will it take the ball to hit the floor? 1.45 secs 1.14 secs 0.28 secs 0.21 secs

1. Yahoo!

Do..u knw kinematics equations of motion

2. kiamonstaa

um.....no

3. lgbasallote

^^that sounds like physics

4. Yahoo!

V = u + at

5. kiamonstaa

um... i thought it was H(t)= -16t^2+vt+s

6. sauravshakya

first we need to convert feet to meter

7. kiamonstaa

ok...whats next

8. sauravshakya

then the time it takes to reach the maximum height

9. kiamonstaa

wait why do i change it from feet to meters?

10. sauravshakya

because we are going to use a=g=-9.81m/s^2

11. kiamonstaa

oh okay

12. sauravshakya

Now, can u?

13. kiamonstaa

whats the a and g? sorry

14. sauravshakya

that is accleration

15. kiamonstaa

ok.......walk me through

16. sauravshakya

convert 3.9 feet into meter

17. kiamonstaa

18. sauravshakya

14.8 feet per second in meter per second?

19. kiamonstaa

oh okay 4 meters and something

20. sauravshakya

3.9 feet = 1.18872m and 14.8 feet per second=4.51104 meter per second

21. sauravshakya

now,v=u+at 0=4.51 + (-9.81)t t=0.46seconds

22. sauravshakya

Again, v^2=u^2+2as 0^2=(4.51)^2 + 2(-9.81)s s=1.04 m

23. sauravshakya

So, maximum height = 1.19+1.04 m = 2.23m

24. sauravshakya

Now, s=ut+1/2 at^2 2.23 = 0*t + 1/2 (9.81) t^2 t=0.67 seconds

25. sauravshakya

So, total time = 0.46+0.67 =1.13 seconds

26. sauravshakya

got it?

27. kiamonstaa

ohh okay.

28. kiamonstaa

thanks

29. sauravshakya

welcome