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sheldon16

  • 2 years ago

What is the solution to the equation log4 x – log4 2 = 3 ?

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  1. sheldon16
    • 2 years ago
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    help anyone

  2. Eyad
    • 2 years ago
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    Use The Property LogX-LogY=Log(X/y)

  3. Eyad
    • 2 years ago
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    Any Hint ?

  4. sheldon16
    • 2 years ago
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    show me an example

  5. hartnn
    • 2 years ago
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    try to use this formula: \[\log_{4}A-\log_{4}B=\log_{4}\frac{A}{B} \]

  6. sheldon16
    • 2 years ago
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    x/2?

  7. sheldon16
    • 2 years ago
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    1/2

  8. sheldon16
    • 2 years ago
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    can u start it and i finish

  9. hartnn
    • 2 years ago
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    ok,so using that formula,tell me whats \[\log_{4}x-\log_{4}2 =? \]

  10. sheldon16
    • 2 years ago
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    log4 x/2?

  11. hartnn
    • 2 years ago
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    yup :) now lets go ahead...

  12. sheldon16
    • 2 years ago
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    so now what do u do

  13. hartnn
    • 2 years ago
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    if \[\log_{x}y=z \] then \[x^{z}=y\]

  14. hartnn
    • 2 years ago
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    here u have \[\log_{4}(x/2)=3 \] so what do u get from this?

  15. sheldon16
    • 2 years ago
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    idk

  16. sheldon16
    • 2 years ago
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    do u multpy something or what

  17. sheldon16
    • 2 years ago
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    eyad help please

  18. Eyad
    • 2 years ago
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    Change it To exponential .... 4^3=x/2 64=x/2 =====> multiply by 2 x=128

  19. Eyad
    • 2 years ago
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    Got It ?

  20. sheldon16
    • 2 years ago
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    oh ok thnx so much now i understand

  21. Eyad
    • 2 years ago
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    COoOL ,Yw ..

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