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sheldon16
Group Title
What is the solution to the equation log4 x – log4 2 = 3 ?
 one year ago
 one year ago
sheldon16 Group Title
What is the solution to the equation log4 x – log4 2 = 3 ?
 one year ago
 one year ago

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sheldon16 Group TitleBest ResponseYou've already chosen the best response.0
help anyone
 one year ago

Eyad Group TitleBest ResponseYou've already chosen the best response.3
Use The Property LogXLogY=Log(X/y)
 one year ago

sheldon16 Group TitleBest ResponseYou've already chosen the best response.0
show me an example
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
try to use this formula: \[\log_{4}A\log_{4}B=\log_{4}\frac{A}{B} \]
 one year ago

sheldon16 Group TitleBest ResponseYou've already chosen the best response.0
can u start it and i finish
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ok,so using that formula,tell me whats \[\log_{4}x\log_{4}2 =? \]
 one year ago

sheldon16 Group TitleBest ResponseYou've already chosen the best response.0
log4 x/2?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yup :) now lets go ahead...
 one year ago

sheldon16 Group TitleBest ResponseYou've already chosen the best response.0
so now what do u do
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
if \[\log_{x}y=z \] then \[x^{z}=y\]
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
here u have \[\log_{4}(x/2)=3 \] so what do u get from this?
 one year ago

sheldon16 Group TitleBest ResponseYou've already chosen the best response.0
do u multpy something or what
 one year ago

sheldon16 Group TitleBest ResponseYou've already chosen the best response.0
eyad help please
 one year ago

Eyad Group TitleBest ResponseYou've already chosen the best response.3
Change it To exponential .... 4^3=x/2 64=x/2 =====> multiply by 2 x=128
 one year ago

sheldon16 Group TitleBest ResponseYou've already chosen the best response.0
oh ok thnx so much now i understand
 one year ago
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