## moongazer 3 years ago What is the oxidation number of all elements in MnSO4

1. moongazer

I already know the rules in finding the oxidation number I just don't know how to get it in this one.

2. Australopithecus

Sulfate has a charge of -2

3. Australopithecus

Thus we can conclude that Magnesium would have a charge of +2

4. Australopithecus

I would assume

5. moongazer

It is from KMnO4 + KCl + H2SO4 = K2SO4 + MnSO4+Cl2+H2O I already determined the other oxidation number from this except for MnSO4

6. moongazer

How about for oxygen? isn't it it should have an oxidation number of -2 ?

7. shubham.bagrecha

MnSO4 +H2O ----> Mn^(2+) + SO4^(2-)

8. Australopithecus

Oxygen, -2, -2, -2, -2 Sulpher is a less electronegative element so it will give up its electrons more readily S has +6 6 -2 -2 -2 - 2 = -2 charge total

9. Australopithecus

I could be wrong, as I'm going off what I have read on Wikipedia and my knowledge of chemistry

10. Australopithecus

I'm basing this on the fact in Oxygen Diflouride OF2 Oxygen has a charge of +2 instead of -2 because fluoride is more electronegative than oxygen

11. Australopithecus

and since PO4 is a polyatomic anion, I would expect it to maintain its integrity while bonded to manganese, although this is speculation on my part I hope it is helpful.

12. Australopithecus

If you have any questions feel free to ask

13. moongazer

So the oxidation numbers will be Mn(+2)S(+6)O4(-2) I based in your statement "Sulfate has a charge of -2 Thus we can conclude that Magnesium would have a charge of +2"

14. moongazer

Is it correct?

15. Australopithecus

O4 should probably have a charge of -8 if S has a charge of +6

16. Australopithecus

but your conclusion seems correct other wise, Remember Oxygen can attract and hold electrons better than sulfer, so sulfer basically becomes an electron source for the oxygen so they can be more like Neon, making Sulfer more like Neon as well instead of what it usually wants to be like Argon

17. Australopithecus

I'm pretty sure the -2 charge is just distributed through out all the oxygen atoms until manganese comes along and donates 2 of its electrons

18. Australopithecus

wait you are probably correct if it is asking for the charge of each individual atom separately :)

19. moongazer

I am getting all the oxidation numbers separately for balancing. Thanks :)

20. Australopithecus

To be honest with you I have never had to answer a question like this I dont think

21. Australopithecus

But I have taken a lot of chemistry courses in my life so I dont know that has to count for something

22. moongazer

Did you mean you haven't balanced a reaction using the oxidation state change method ?

23. moongazer

anyway, thanks for the help :)

24. Australopithecus

yeah

25. Australopithecus

I had some other method when I did these problems that I cannot remember, but yeah no problem thanks for the question chemistry problems subside the insanity for me :)