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zaphod

A falling stone takes 0.2 seconds to fall past a window which is 1 m high. From how far above the top of the window was the stone dropped?

  • one year ago
  • one year ago

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  1. zaphod
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    @sauravshakya

    • one year ago
  2. zaphod
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    shall i show the working?

    • one year ago
  3. sauravshakya
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    Yep

    • one year ago
  4. zaphod
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    s= ut +1/2at^2 s- 1 = 1/2 * 9.81 * (0.2)^2 s = 1.196

    • one year ago
  5. sauravshakya
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    s=ut+1/2 at^2 x=0+1/2 * 9.81 * (0.2)^2 x=0.196 m

    • one year ago
  6. sauravshakya
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    Is the answer 0.196m

    • one year ago
  7. zaphod
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    but the answer is 0.82

    • one year ago
  8. sauravshakya
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    oh got it..

    • one year ago
  9. sauravshakya
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    Actually, s= ut + 1/2 at^2 1 = u*0.2 + 1/2 (9.81) *(0.2^2) u=4.02 m/s

    • one year ago
  10. zaphod
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    a falling stone right

    • one year ago
  11. sauravshakya
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    Now, v^2=u^2+2as (4.02)^2=0^2+2*(9.81)*x x=0.82m

    • one year ago
  12. sauravshakya
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    Yes, the falling stone takes 0.2 seconds to reach the ground from the window

    • one year ago
  13. sauravshakya
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    got it?

    • one year ago
  14. zaphod
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    |dw:1345877484628:dw|

    • one year ago
  15. zaphod
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    can u drw a diagram?

    • one year ago
  16. zaphod
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    oh i get it:)

    • one year ago
  17. sauravshakya
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    @zaphod u there?

    • one year ago
  18. zaphod
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    i understood thnks bro:)

    • one year ago
  19. sauravshakya
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    |dw:1345878136099:dw|Actually its:

    • one year ago
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