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zaphod

  • 3 years ago

A falling stone takes 0.2 seconds to fall past a window which is 1 m high. From how far above the top of the window was the stone dropped?

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  1. zaphod
    • 3 years ago
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    @sauravshakya

  2. zaphod
    • 3 years ago
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    shall i show the working?

  3. sauravshakya
    • 3 years ago
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    Yep

  4. zaphod
    • 3 years ago
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    s= ut +1/2at^2 s- 1 = 1/2 * 9.81 * (0.2)^2 s = 1.196

  5. sauravshakya
    • 3 years ago
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    s=ut+1/2 at^2 x=0+1/2 * 9.81 * (0.2)^2 x=0.196 m

  6. sauravshakya
    • 3 years ago
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    Is the answer 0.196m

  7. zaphod
    • 3 years ago
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    but the answer is 0.82

  8. sauravshakya
    • 3 years ago
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    oh got it..

  9. sauravshakya
    • 3 years ago
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    Actually, s= ut + 1/2 at^2 1 = u*0.2 + 1/2 (9.81) *(0.2^2) u=4.02 m/s

  10. zaphod
    • 3 years ago
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    a falling stone right

  11. sauravshakya
    • 3 years ago
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    Now, v^2=u^2+2as (4.02)^2=0^2+2*(9.81)*x x=0.82m

  12. sauravshakya
    • 3 years ago
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    Yes, the falling stone takes 0.2 seconds to reach the ground from the window

  13. sauravshakya
    • 3 years ago
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    got it?

  14. zaphod
    • 3 years ago
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    |dw:1345877484628:dw|

  15. zaphod
    • 3 years ago
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    can u drw a diagram?

  16. zaphod
    • 3 years ago
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    oh i get it:)

  17. sauravshakya
    • 3 years ago
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    @zaphod u there?

  18. zaphod
    • 3 years ago
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    i understood thnks bro:)

  19. sauravshakya
    • 3 years ago
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    |dw:1345878136099:dw|Actually its:

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