anonymous
  • anonymous
A falling stone takes 0.2 seconds to fall past a window which is 1 m high. From how far above the top of the window was the stone dropped?
Physics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@sauravshakya
anonymous
  • anonymous
shall i show the working?
anonymous
  • anonymous
Yep

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anonymous
  • anonymous
s= ut +1/2at^2 s- 1 = 1/2 * 9.81 * (0.2)^2 s = 1.196
anonymous
  • anonymous
s=ut+1/2 at^2 x=0+1/2 * 9.81 * (0.2)^2 x=0.196 m
anonymous
  • anonymous
Is the answer 0.196m
anonymous
  • anonymous
but the answer is 0.82
anonymous
  • anonymous
oh got it..
anonymous
  • anonymous
Actually, s= ut + 1/2 at^2 1 = u*0.2 + 1/2 (9.81) *(0.2^2) u=4.02 m/s
anonymous
  • anonymous
a falling stone right
anonymous
  • anonymous
Now, v^2=u^2+2as (4.02)^2=0^2+2*(9.81)*x x=0.82m
anonymous
  • anonymous
Yes, the falling stone takes 0.2 seconds to reach the ground from the window
anonymous
  • anonymous
got it?
anonymous
  • anonymous
|dw:1345877484628:dw|
anonymous
  • anonymous
can u drw a diagram?
anonymous
  • anonymous
oh i get it:)
anonymous
  • anonymous
@zaphod u there?
anonymous
  • anonymous
i understood thnks bro:)
anonymous
  • anonymous
|dw:1345878136099:dw|Actually its:

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