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moongazer
 4 years ago
In graphing trigonometric functions why is it the phase shift of
y = a sin b(x+c) + d .
when c < 0 is to the right and when c > 0 is to the left ??
also for other trigo functions
moongazer
 4 years ago
In graphing trigonometric functions why is it the phase shift of y = a sin b(x+c) + d . when c < 0 is to the right and when c > 0 is to the left ?? also for other trigo functions

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3to allow us to determine this from the origin

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3dw:1345902565889:dw

phi
 4 years ago
Best ResponseYou've already chosen the best response.0the same reason that f(x1) is shifted to the right. When x is 0, you plot a value taken from the function to the left of zero. You have "moved the point on the left to the right"

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3does this make sense?

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.1I'm still trying to understand it :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3evaluating things that are at the origin, is by far simpler than trying to evaluate them at a distance.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3since moving an object doesnt change its inherent structure; we move it to the origin to study it

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3we account for the movement in the equation such that if we move the center to the origin; all the points related to the function move in the same manner

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.1I think I understood it now with the explanation of phi.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3if we want to study a parabola: y = (x)^2 ; such that the vertex is x = 5, y=3 it is better to study this when the vertex is at the origin so we move it by 5, 3 to get it to (0,0) y3 = (x5)^2 y = (x5)^2 + 3

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3if x is out of phase by a factor of "c" then we need to adjust this thing back into place with (xc)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3i think factor is a bad term there, but you know .....

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.1That's what I am thinking with this sine graph dw:1345904532767:dw you need to subtract pi/3 to make it to the origin

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.1I think what you said: "then we need to adjust this thing back into place with (xc)" explains it

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.1could you also explain why a is the amplitude and d is the vertical shift?

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.1I'm just curious how does that work :)

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1when u write y=a sin (b(x+c)) the maximum value of y is a because the maximum value of sine function is 1 and the amplitude is the maximum value a function can take....

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1now consider the equation yd=a sin (b(x+c)) this means that all the points with ycoordinate y has now the y coordinate of yd this is a vertical shift of the entire function if d is positive, the entire function shifts down by d units and if d is negative the entire function shifts up by d units

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1i hope u got this @moongazer

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3a is a scalar factor that affects the slope of this thing at any given point. if we take the sine wave, it only has values from 1 to 1, the "a" part manipulates the slope at every given point to change how high or low the sin function can reach

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3sin(90) = 1; but lets say the original function is such that sin(90) = 3; multiply both sides by 3 3 sin(90) = 3

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3hartnn looks to have explained that well

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.1Thanks for the answers. I agree that hartnn explained it well. :)
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