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hawkfalcon

simplify sinθ*sec^2(90-θ)

  • one year ago
  • one year ago

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  1. hawkfalcon
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    Simplify

    • one year ago
  2. hawkfalcon
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    \[\sinθ*\sec^2(90-θ)\]

    • one year ago
  3. dumbcow
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    using the sum/difference angle identities you can see that \[\cos(90-\theta) = \cos(90)\cos(\theta) + \sin(90)\sin(\theta) = \sin(\theta)\] thus \[\sec^{2}(90-\theta) = \csc(\theta)\]

    • one year ago
  4. dumbcow
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    sorry that should be csc^2

    • one year ago
  5. NoelGreco
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    sec(90-theta) is the secant of the COmplement of theta or the COsecant theta.

    • one year ago
  6. hawkfalcon
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    Oh okay:3 that makes sense. Thank you!:D

    • one year ago
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