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hawkfalcon

  • 3 years ago

simplify sinθ*sec^2(90-θ)

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  1. hawkfalcon
    • 3 years ago
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    Simplify

  2. hawkfalcon
    • 3 years ago
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    \[\sinθ*\sec^2(90-θ)\]

  3. dumbcow
    • 3 years ago
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    using the sum/difference angle identities you can see that \[\cos(90-\theta) = \cos(90)\cos(\theta) + \sin(90)\sin(\theta) = \sin(\theta)\] thus \[\sec^{2}(90-\theta) = \csc(\theta)\]

  4. dumbcow
    • 3 years ago
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    sorry that should be csc^2

  5. NoelGreco
    • 3 years ago
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    sec(90-theta) is the secant of the COmplement of theta or the COsecant theta.

  6. hawkfalcon
    • 3 years ago
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    Oh okay:3 that makes sense. Thank you!:D

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