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mitchelsewbaran

Which statement describes the translation of y= -1/2(x-2)^2 from standard position? Moved up and to the right. Moved up and to the left. Moved down and to the left. Moved down and to the right.

  • one year ago
  • one year ago

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  1. hal_stirrup
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    Trigonometry: Angles Standard Position Angles can exist anywhere in the coordinate plane where two rays share a common vertex. If this vertex is at the origin of the plane and the initial side lies along the positive $x$-axis, then the angle is said to be in standard position.

    • one year ago
  2. mitchelsewbaran
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    s which statement would it be?

    • one year ago
  3. hal_stirrup
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    if tell you if y=-1 which quadrant it in . 1st 2nd 3ed or 4th ???????

    • one year ago
  4. mitchelsewbaran
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    3rd and 4th. it's a straight line

    • one year ago
  5. hal_stirrup
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    ok good.

    • one year ago
  6. hal_stirrup
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    look at the equation carefully and see!! \[y=-\frac{ 1 }{ 2(x-2)^{2} }\]

    • one year ago
  7. hal_stirrup
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    (X-2)^2 =???

    • one year ago
  8. hal_stirrup
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    x^2 -4x+4 right!!

    • one year ago
  9. hal_stirrup
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    so -1 tells us its in 3rd or 4th so we know that!! what can we do now!!

    • one year ago
  10. mitchelsewbaran
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    idk

    • one year ago
  11. hal_stirrup
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    2(x^2 -4x+4)=2x^2-8x+8 right

    • one year ago
  12. hal_stirrup
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    this is quadratic equation right!

    • one year ago
  13. hal_stirrup
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    tell me if you dont undertand me plz

    • one year ago
  14. mitchelsewbaran
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    yes it is

    • one year ago
  15. hal_stirrup
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    find it roots and you would know.

    • one year ago
  16. mitchelsewbaran
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    find the roots of which equation?

    • one year ago
  17. hal_stirrup
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    2x^2-8x+8

    • one year ago
  18. mitchelsewbaran
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    1, 1/2, 2, 4, 8

    • one year ago
  19. mitchelsewbaran
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    hello?

    • one year ago
  20. hal_stirrup
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    root is 2

    • one year ago
  21. mitchelsewbaran
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    o

    • one year ago
  22. hal_stirrup
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    do you have the book answer??

    • one year ago
  23. mitchelsewbaran
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    no

    • one year ago
  24. mitchelsewbaran
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    • one year ago
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  25. hal_stirrup
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    what you have written and what you have in the image are two different equations !!

    • one year ago
  26. mitchelsewbaran
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    well this was the actual question. my bad!!!

    • one year ago
  27. mitchelsewbaran
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    the attachment

    • one year ago
  28. hal_stirrup
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    Regardless what i showed you should make you answer the question.

    • one year ago
  29. mitchelsewbaran
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    the 1st one

    • one year ago
  30. hal_stirrup
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    ?? "the 1st one"

    • one year ago
  31. mitchelsewbaran
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    the 1st choices out of the 4 i provided

    • one year ago
  32. mitchelsewbaran
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    Moved up and to the right.

    • one year ago
  33. hal_stirrup
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    ok do the following . get a graphic calculator or software and plug in you equation.see for you self as am seing know, its not 1st choices. i hope am wrong so i learn something new here. i really do!!

    • one year ago
  34. mitchelsewbaran
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    plug in the equation from the question, or 2x^2-8x+8?

    • one year ago
  35. hal_stirrup
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    plug this y=-1/2 (x-2)^2 -(2)

    • one year ago
  36. mitchelsewbaran
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    • one year ago
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  37. hal_stirrup
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    so how can it be Moved up and to the right

    • one year ago
  38. mitchelsewbaran
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    ok, well fine, i'm wrong...

    • one year ago
  39. hal_stirrup
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    am not here help . i hope i did that.

    • one year ago
  40. mitchelsewbaran
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    hope u did what?

    • one year ago
  41. hal_stirrup
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    sorry i mean am here to help . i hope i did that

    • one year ago
  42. hal_stirrup
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    |dw:1345942197493:dw|

    • one year ago
  43. mitchelsewbaran
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    so it can be moved down then to the right?

    • one year ago
  44. hal_stirrup
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    thats what i think.

    • one year ago
  45. hal_stirrup
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    |dw:1345942387443:dw|

    • one year ago
  46. hal_stirrup
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    where did you get this Q from??

    • one year ago
  47. hal_stirrup
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    |dw:1345942587752:dw|

    • one year ago
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