anonymous
  • anonymous
I was working on an MVC problem but forgot my trig: \(\sin(\pi-x) = ?\). It's like negative cosine or something, right?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
I think it's regular sine....
anonymous
  • anonymous
yes
anonymous
  • anonymous
Yeah probably b/c sin(pi-x) = -sin(x-pi), and that's just flip n' shift

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anonymous
  • anonymous
i means yes, it is sine
anonymous
  • anonymous
lol ok
anonymous
  • anonymous
@satellite73 while you're here - is there anyway of simplifying \[\sin(\arcsin(c_1\sin\Phi)+\alpha)\] Maybe with the sum of angles for sines we can cancel out a sin/arcsin term - or will we be stuck with a cos(arcsin) term?
anonymous
  • anonymous
nvm ill ask a question seperately.

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