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vf321

  • 2 years ago

I was working on an MVC problem but forgot my trig: \(\sin(\pi-x) = ?\). It's like negative cosine or something, right?

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  1. vf321
    • 2 years ago
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    I think it's regular sine....

  2. satellite73
    • 2 years ago
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    yes

  3. vf321
    • 2 years ago
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    Yeah probably b/c sin(pi-x) = -sin(x-pi), and that's just flip n' shift

  4. satellite73
    • 2 years ago
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    i means yes, it is sine

  5. vf321
    • 2 years ago
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    lol ok

  6. vf321
    • 2 years ago
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    @satellite73 while you're here - is there anyway of simplifying \[\sin(\arcsin(c_1\sin\Phi)+\alpha)\] Maybe with the sum of angles for sines we can cancel out a sin/arcsin term - or will we be stuck with a cos(arcsin) term?

  7. vf321
    • 2 years ago
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    nvm ill ask a question seperately.

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