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pratu043

  • 2 years ago

If S is any point in the interior of triangle PQR then prove that SQ + SR < PQ + QR.

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  1. pratu043
    • 2 years ago
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    |dw:1345956288365:dw|

  2. pratu043
    • 2 years ago
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    someone please help!!

  3. pratu043
    • 2 years ago
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    please!!!

  4. mukushla
    • 2 years ago
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    sorry can u check it plz... i have some doubt on it SQ + SR < PQ + QR or SQ + SR < PQ + PR

  5. pratu043
    • 2 years ago
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    sorry its SQ + SR < PQ + PR.

  6. jiteshmeghwal9
    • 2 years ago
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    Does it help @pratu043 ??? \[\LARGE{s=90^o+{1 \over 2} \angle a}\]

  7. SNSDYoona
    • 2 years ago
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    was wondering if i could use vectors to proof it? or u want basic trigonometries?

  8. TheMind
    • 2 years ago
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    the perimeter of tri PQR > the perimeter of tri SQR because S is inside PQR. in other word PQ+QR+PR > SQ+QR+SR take out the positive amount QR from both side PQ+PR > SQ+SR

  9. pratu043
    • 2 years ago
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    Thank you @TheMind

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