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anonymous
 3 years ago
If S is any point in the interior of triangle PQR then prove that SQ + SR < PQ + QR.
anonymous
 3 years ago
If S is any point in the interior of triangle PQR then prove that SQ + SR < PQ + QR.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1345956288365:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0someone please help!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry can u check it plz... i have some doubt on it SQ + SR < PQ + QR or SQ + SR < PQ + PR

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry its SQ + SR < PQ + PR.

jiteshmeghwal9
 3 years ago
Best ResponseYou've already chosen the best response.1Does it help @pratu043 ??? \[\LARGE{s=90^o+{1 \over 2} \angle a}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0was wondering if i could use vectors to proof it? or u want basic trigonometries?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the perimeter of tri PQR > the perimeter of tri SQR because S is inside PQR. in other word PQ+QR+PR > SQ+QR+SR take out the positive amount QR from both side PQ+PR > SQ+SR
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