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pratu043
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If S is any point in the interior of triangle PQR then prove that SQ + SR < PQ + QR.
 one year ago
 one year ago
pratu043 Group Title
If S is any point in the interior of triangle PQR then prove that SQ + SR < PQ + QR.
 one year ago
 one year ago

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pratu043 Group TitleBest ResponseYou've already chosen the best response.0
dw:1345956288365:dw
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
someone please help!!
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
please!!!
 one year ago

mukushla Group TitleBest ResponseYou've already chosen the best response.0
sorry can u check it plz... i have some doubt on it SQ + SR < PQ + QR or SQ + SR < PQ + PR
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
sorry its SQ + SR < PQ + PR.
 one year ago

jiteshmeghwal9 Group TitleBest ResponseYou've already chosen the best response.1
Does it help @pratu043 ??? \[\LARGE{s=90^o+{1 \over 2} \angle a}\]
 one year ago

SNSDYoona Group TitleBest ResponseYou've already chosen the best response.0
was wondering if i could use vectors to proof it? or u want basic trigonometries?
 one year ago

TheMind Group TitleBest ResponseYou've already chosen the best response.1
the perimeter of tri PQR > the perimeter of tri SQR because S is inside PQR. in other word PQ+QR+PR > SQ+QR+SR take out the positive amount QR from both side PQ+PR > SQ+SR
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
Thank you @TheMind
 one year ago
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