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If S is any point in the interior of triangle PQR then prove that SQ + SR < PQ + QR.
 one year ago
 one year ago
If S is any point in the interior of triangle PQR then prove that SQ + SR < PQ + QR.
 one year ago
 one year ago

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pratu043Best ResponseYou've already chosen the best response.0
dw:1345956288365:dw
 one year ago

pratu043Best ResponseYou've already chosen the best response.0
someone please help!!
 one year ago

mukushlaBest ResponseYou've already chosen the best response.0
sorry can u check it plz... i have some doubt on it SQ + SR < PQ + QR or SQ + SR < PQ + PR
 one year ago

pratu043Best ResponseYou've already chosen the best response.0
sorry its SQ + SR < PQ + PR.
 one year ago

jiteshmeghwal9Best ResponseYou've already chosen the best response.1
Does it help @pratu043 ??? \[\LARGE{s=90^o+{1 \over 2} \angle a}\]
 one year ago

SNSDYoonaBest ResponseYou've already chosen the best response.0
was wondering if i could use vectors to proof it? or u want basic trigonometries?
 one year ago

TheMindBest ResponseYou've already chosen the best response.1
the perimeter of tri PQR > the perimeter of tri SQR because S is inside PQR. in other word PQ+QR+PR > SQ+QR+SR take out the positive amount QR from both side PQ+PR > SQ+SR
 one year ago
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