Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

mandonut Group Title

The light turns green, and a bicyclist starts forward with an acceleration of 1.2m/s^2 . How far must she travel to reach a speed of 8.0m/s ?

  • 2 years ago
  • 2 years ago

  • This Question is Open
  1. RanjanSahu Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Quite simple... Use the 3rd Kinematic Equation \[v ^{2}=u ^{2}+2as\]Here; Initial velocity, u=0m/s Final velocity, v=8.0m/s Acceleration, a=1.2m/s^2 Displacement, s=? Substituting the values in the above equation; 8^2=0^2 + 2*1.2*s 64=2.4*s s=64/2.4 s=2.666m Therefore, the bicyclist must travel 2.666m to reach a speed of 8m/s.

    • 2 years ago
  2. RanjanSahu Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Thanks... Demitris for correcting me. I don't know about US or foreign education system but in Indian edu. system we can use any of those 3 equations and call them the 3 kinematic equation of motion. There is no such restriction on the usage of only first 2 equation.

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.