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anonymous
 4 years ago
Find the solution to this system using the substitution method. 2x 5y = 1 and x 3y = 3
anonymous
 4 years ago
Find the solution to this system using the substitution method. 2x 5y = 1 and x 3y = 3

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mathslover
 4 years ago
Best ResponseYou've already chosen the best response.22x5y = 1 2x = 1 + 5y x = \(\large{\frac{1+5y}{2}}\)

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.2put this value in the second eqn : \[\large{x3y=3}\] \[\large{\frac{1+5y}{2}3y=3}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0form the second equation we have x=3y 3 putting it in the first we have 2(3y3)5y=1 or 6y 65y =1 or y=61 or y=5 hence x=3(5) 3=12 x=12 and y=5

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.2\[\large{\frac{1+5y6y}{2}=3}\] \[\large{1y=6}\] \[\large{1+6=y}\] \[\large{5=y}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its too sticky and icky...mmmmmm

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.2similarly find x x 3(5) = 3 x15=3 x = 3+15
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