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Find the solution to this system using the substitution method. 2x 5y = 1 and x 3y = 3
 one year ago
 one year ago
Find the solution to this system using the substitution method. 2x 5y = 1 and x 3y = 3
 one year ago
 one year ago

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mathsloverBest ResponseYou've already chosen the best response.2
2x5y = 1 2x = 1 + 5y x = \(\large{\frac{1+5y}{2}}\)
 one year ago

mathsloverBest ResponseYou've already chosen the best response.2
put this value in the second eqn : \[\large{x3y=3}\] \[\large{\frac{1+5y}{2}3y=3}\]
 one year ago

matrickedBest ResponseYou've already chosen the best response.1
form the second equation we have x=3y 3 putting it in the first we have 2(3y3)5y=1 or 6y 65y =1 or y=61 or y=5 hence x=3(5) 3=12 x=12 and y=5
 one year ago

mathsloverBest ResponseYou've already chosen the best response.2
\[\large{\frac{1+5y6y}{2}=3}\] \[\large{1y=6}\] \[\large{1+6=y}\] \[\large{5=y}\]
 one year ago

chemENGINEERBest ResponseYou've already chosen the best response.0
its too sticky and icky...mmmmmm
 one year ago

mathsloverBest ResponseYou've already chosen the best response.2
similarly find x x 3(5) = 3 x15=3 x = 3+15
 one year ago
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