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rannsan
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Find the solution to this system using the substitution method. 2x 5y = 1 and x 3y = 3
 one year ago
 one year ago
rannsan Group Title
Find the solution to this system using the substitution method. 2x 5y = 1 and x 3y = 3
 one year ago
 one year ago

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mathslover Group TitleBest ResponseYou've already chosen the best response.2
2x5y = 1 2x = 1 + 5y x = \(\large{\frac{1+5y}{2}}\)
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
put this value in the second eqn : \[\large{x3y=3}\] \[\large{\frac{1+5y}{2}3y=3}\]
 one year ago

matricked Group TitleBest ResponseYou've already chosen the best response.1
form the second equation we have x=3y 3 putting it in the first we have 2(3y3)5y=1 or 6y 65y =1 or y=61 or y=5 hence x=3(5) 3=12 x=12 and y=5
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
\[\large{\frac{1+5y6y}{2}=3}\] \[\large{1y=6}\] \[\large{1+6=y}\] \[\large{5=y}\]
 one year ago

chemENGINEER Group TitleBest ResponseYou've already chosen the best response.0
its too sticky and icky...mmmmmm
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
similarly find x x 3(5) = 3 x15=3 x = 3+15
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
got it @rannsan ?
 one year ago

rannsan Group TitleBest ResponseYou've already chosen the best response.0
I think so
 one year ago

rannsan Group TitleBest ResponseYou've already chosen the best response.0
Thank you!!
 one year ago
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