## rannsan 3 years ago Find the solution to this system using the substitution method. 2x -5y = -1 and x -3y = -3

1. mathslover

2x-5y = -1 2x = -1 + 5y x = $$\large{\frac{-1+5y}{2}}$$

2. mathslover

put this value in the second eqn : $\large{x-3y=-3}$ $\large{\frac{-1+5y}{2}-3y=-3}$

3. matricked

form the second equation we have x=3y -3 putting it in the first we have 2(3y-3)-5y=-1 or 6y -6-5y =-1 or y=6-1 or y=5 hence x=3(5) -3=12 x=12 and y=5

4. mathslover

$\large{\frac{-1+5y-6y}{2}=-3}$ $\large{-1-y=-6}$ $\large{-1+6=y}$ $\large{5=y}$

5. chemENGINEER

its too sticky and icky...mmmmmm

6. mathslover

similarly find x x- 3(5) = -3 x-15=-3 x = -3+15

7. mathslover

got it @rannsan ?

8. rannsan

I think so

9. rannsan

Thank you!!