A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Use the limit definition to compute the derivative, f'(x),
\[f(x)=\frac { 1 }{ 2 } x\frac { 3 }{ 5 } \]
anonymous
 4 years ago
Use the limit definition to compute the derivative, f'(x), \[f(x)=\frac { 1 }{ 2 } x\frac { 3 }{ 5 } \]

This Question is Closed

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.0oh k progression or in progress? MAN AT WORK :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh wow what a question...!!

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.0rohangrr is typing a reply...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Use the limit definition to compute the derivative, f'(x), \[f(x)=\frac { 1 }{ 2 } x\frac { 3 }{ 5 } \]

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1derivative from the first principle..?

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1345962336537:dw

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{dy}{dx} = \lim_{x \rightarrow 0} \frac{f(x+h)f(x)}{h} \]

Mimi_x3
 4 years ago
Best ResponseYou've already chosen the best response.1mathslover; its from the first principle..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\huge f'\quad (x)\quad =\lim _{ x\rightarrow 0 } \frac { f(x+\triangle x)f(x) }{ \triangle x } \] \[\huge \quad =\lim _{ x\rightarrow 0 } \frac { \frac { 1 }{ 2 } (x+\triangle x)\frac { 3 }{ 5 } \{ \frac { 1 }{ 2 } x\frac { 3 }{ 5 } \} }{ \triangle x } \] What will be after this

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.3first of all the limit would be h>0 !! then u cancel,x/2 and 3/5 in numerator.....

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.3then u will simply get:dw:1345962738189:dw

mathslover
 4 years ago
Best ResponseYou've already chosen the best response.0the same I got but my method was wrong :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\quad =\lim _{ \triangle x\rightarrow 0 } \frac { \frac { 1 }{ 2 } x+\frac { 1 }{ 2 } \triangle x\frac { 3 }{ 5 } \frac { 1 }{ 2 } x+\frac { 3 }{ 5 } \} }{ \triangle x }

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is this the final answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1345963107126:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1345963183321:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1345963244684:dw

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0Do you still have a question?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hi @myininaya I didnt observe u here

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.3First principle: \[f'(x) =\lim_{Δ x \rightarrow 0}\frac{f(x+Δ x)f(x)}{Δ x}\] When \(f(x) = \frac{1}{2}x  \frac{3}{5}\), \[f'(x) =\lim_{Δ x \rightarrow 0}\frac{[\frac{1}{2}(x+Δ x)\frac{3}{5}](\frac{1}{2}x  \frac{3}{5})}{Δ x}\] \[=\lim_{Δ x \rightarrow 0}\frac{\frac{1}{2}x+\frac{1}{2}Δ x\frac{3}{5}\frac{1}{2}x + \frac{3}{5}}{Δ x}\] \[=\lim_{Δ x \rightarrow 0}\frac{\frac{1}{2}Δ x}{Δ x}\] \[=\lim_{Δ x \rightarrow 0}\frac{\frac{1}{2}\cancel{Δ x}}{\cancel{Δ x}}\] \[=\lim_{Δ x \rightarrow 0}\frac{1}{2}\] \[=...\] Wow! I'm tooooo late!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But I am still in confusion now..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0To Whom should I give the medal ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No, it is now clear...
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.