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x2-5x+6=0

y=y
x2=5x-6
..
.
.
.
x=2,3

Can you explain it? I don't really get it

x2-2x-3x+6=0
x(x-2)-3(x-2)=0
(x-2)(x-3)=0

got it?
eliminate y from both equations to get a quadratic equation and solve it

Ok