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amistre64
Group Title
This was fuunn!!!
Create an equation of absolute values with the given properties for the graph
slopes from left to right are: 4, 2, 1, 0, 4
you can define your own vertexes, but it has to match those slopes.
 one year ago
 one year ago
amistre64 Group Title
This was fuunn!!! Create an equation of absolute values with the given properties for the graph slopes from left to right are: 4, 2, 1, 0, 4 you can define your own vertexes, but it has to match those slopes.
 one year ago
 one year ago

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amistre64 Group TitleBest ResponseYou've already chosen the best response.1
no cowering away from a challenge now ;)
 one year ago

magepker728 Group TitleBest ResponseYou've already chosen the best response.0
lol just by looking at it made me slap myself lol
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
with 5 slopes, we would need to setup up a system of 5 equations in 5 unknowns i finally understood the dynamics to determine the slopes this morning
 one year ago

magepker728 Group TitleBest ResponseYou've already chosen the best response.0
well if you can explain how to do it, ill really appreciate it
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
spose we name the parts for each slope as: a,b,c,d we can construct the equations as such abcd = 4 abc+d = 2 ab+c+d = 1 a+b+c+d=0 this gives us a solutions to:\[y=axv_1+bxv_2+cxv_3+dxv_4\] where the vs are the vertexes from left to right as well
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
since the first and last slopes are just multiples of each other, we can do this one with 4 equations
 one year ago

magepker728 Group TitleBest ResponseYou've already chosen the best response.0
wow never taught of it this way lol.. looks like i have another problem to copy and save in my folder lol
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i had never had the notion to even consider this until a post about it yesterday that i was on
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i sat there this morning with my trusty little ti83; and wrote out an equation to test the dynamic with y = 2xv1+xv2+2xv3 and i found out that the corresponding graph had slopes between verts that matched up with: (2+1+2) (2+12) (212) (212)
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
replacing my known slopes with a b and c defined a general setup :) yay
 one year ago

magepker728 Group TitleBest ResponseYou've already chosen the best response.0
your amazing lol
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
im curious if i introduce a derivative as a slope if i can get a section between verts to be a curve
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
rref{{1,1,1,1,4},{1,1,1,1,2},{1,1,1,1,1},{1,1,1,1,0}} the wolf gives me a matrix read out of the abcd so that y = 2x+2 x/2+3x2/2+x5  10 ;  10 just to drop it down hmm, but its reversed, right to left lol http://www.wolframalpha.com/input/?i=y+%3D+2%7Cx%2B2%7C+%7Cx%7C%2F2%2B3%7Cx2%7C%2F2%2B%7Cx5%7C++10
 one year ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i guess we can forgo the negative in front .... of my setups :)
 one year ago
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