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amistre64
 4 years ago
This was fuunn!!!
Create an equation of absolute values with the given properties for the graph
slopes from left to right are: 4, 2, 1, 0, 4
you can define your own vertexes, but it has to match those slopes.
amistre64
 4 years ago
This was fuunn!!! Create an equation of absolute values with the given properties for the graph slopes from left to right are: 4, 2, 1, 0, 4 you can define your own vertexes, but it has to match those slopes.

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1no cowering away from a challenge now ;)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol just by looking at it made me slap myself lol

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1with 5 slopes, we would need to setup up a system of 5 equations in 5 unknowns i finally understood the dynamics to determine the slopes this morning

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well if you can explain how to do it, ill really appreciate it

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1spose we name the parts for each slope as: a,b,c,d we can construct the equations as such abcd = 4 abc+d = 2 ab+c+d = 1 a+b+c+d=0 this gives us a solutions to:\[y=axv_1+bxv_2+cxv_3+dxv_4\] where the vs are the vertexes from left to right as well

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1since the first and last slopes are just multiples of each other, we can do this one with 4 equations

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wow never taught of it this way lol.. looks like i have another problem to copy and save in my folder lol

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i had never had the notion to even consider this until a post about it yesterday that i was on

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i sat there this morning with my trusty little ti83; and wrote out an equation to test the dynamic with y = 2xv1+xv2+2xv3 and i found out that the corresponding graph had slopes between verts that matched up with: (2+1+2) (2+12) (212) (212)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1replacing my known slopes with a b and c defined a general setup :) yay

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1im curious if i introduce a derivative as a slope if i can get a section between verts to be a curve

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1rref{{1,1,1,1,4},{1,1,1,1,2},{1,1,1,1,1},{1,1,1,1,0}} the wolf gives me a matrix read out of the abcd so that y = 2x+2 x/2+3x2/2+x5  10 ;  10 just to drop it down hmm, but its reversed, right to left lol http://www.wolframalpha.com/input/?i=y+%3D+2%7Cx%2B2%7C+%7Cx%7C%2F2%2B3%7Cx2%7C%2F2%2B%7Cx5%7C++10

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.1i guess we can forgo the negative in front .... of my setups :)
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