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amistre64
Group Title
This was fuunn!!!
Create an equation of absolute values with the given properties for the graph
slopes from left to right are: 4, 2, 1, 0, 4
you can define your own vertexes, but it has to match those slopes.
 2 years ago
 2 years ago
amistre64 Group Title
This was fuunn!!! Create an equation of absolute values with the given properties for the graph slopes from left to right are: 4, 2, 1, 0, 4 you can define your own vertexes, but it has to match those slopes.
 2 years ago
 2 years ago

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amistre64 Group TitleBest ResponseYou've already chosen the best response.1
no cowering away from a challenge now ;)
 2 years ago

magepker728 Group TitleBest ResponseYou've already chosen the best response.0
lol just by looking at it made me slap myself lol
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
with 5 slopes, we would need to setup up a system of 5 equations in 5 unknowns i finally understood the dynamics to determine the slopes this morning
 2 years ago

magepker728 Group TitleBest ResponseYou've already chosen the best response.0
well if you can explain how to do it, ill really appreciate it
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
spose we name the parts for each slope as: a,b,c,d we can construct the equations as such abcd = 4 abc+d = 2 ab+c+d = 1 a+b+c+d=0 this gives us a solutions to:\[y=axv_1+bxv_2+cxv_3+dxv_4\] where the vs are the vertexes from left to right as well
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
since the first and last slopes are just multiples of each other, we can do this one with 4 equations
 2 years ago

magepker728 Group TitleBest ResponseYou've already chosen the best response.0
wow never taught of it this way lol.. looks like i have another problem to copy and save in my folder lol
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i had never had the notion to even consider this until a post about it yesterday that i was on
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i sat there this morning with my trusty little ti83; and wrote out an equation to test the dynamic with y = 2xv1+xv2+2xv3 and i found out that the corresponding graph had slopes between verts that matched up with: (2+1+2) (2+12) (212) (212)
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
replacing my known slopes with a b and c defined a general setup :) yay
 2 years ago

magepker728 Group TitleBest ResponseYou've already chosen the best response.0
your amazing lol
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
im curious if i introduce a derivative as a slope if i can get a section between verts to be a curve
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
rref{{1,1,1,1,4},{1,1,1,1,2},{1,1,1,1,1},{1,1,1,1,0}} the wolf gives me a matrix read out of the abcd so that y = 2x+2 x/2+3x2/2+x5  10 ;  10 just to drop it down hmm, but its reversed, right to left lol http://www.wolframalpha.com/input/?i=y+%3D+2%7Cx%2B2%7C+%7Cx%7C%2F2%2B3%7Cx2%7C%2F2%2B%7Cx5%7C++10
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.1
i guess we can forgo the negative in front .... of my setups :)
 2 years ago
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