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D={x: where x belong to R and x >=17}
R={ y>=0}

so, would it be 18x-17>=0? and solve?

is this your function: \(\large f(x)=18\sqrt{x}-17 \)

yes

|dw:1346012919057:dw|

so the actual question in finding the domain is "what x values is \(\large \sqrt x =real\) number

would I do.. 18x-17<0 and solve?

x>=-17

root of x is always larger than 0

-17?

so.. [-17,infinity) ?

That is your range, yes.

how do I find the domain with this function?

(-inf,inf) ?

anything that is NOT a "no-no", sorry ;]

1?

so.. 17?

|dw:1346014535907:dw|

so x is all real numbers that are positive then?

Yep, or in other words x >= 0

how do I put that into interval notation though? [0,inf)