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TheMind Group TitleBest ResponseYou've already chosen the best response.0
D={x: where x belong to R and x >=17} R={ y>=0}
 2 years ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
so, would it be 18x17>=0? and solve?
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
is this your function: \(\large f(x)=18\sqrt{x}17 \)
 2 years ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
dw:1346012919057:dw
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
the domain of f is all the x values that give f(x) a real value.... so looking at the function, the function will not give you a real number when x is less than 0....
 2 years ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.0
so the actual question in finding the domain is "what x values is \(\large \sqrt x =real\) number
 2 years ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
would I do.. 18x17<0 and solve?
 2 years ago

love_math Group TitleBest ResponseYou've already chosen the best response.0
root of x is always larger than 0
 2 years ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
You're just looking to be sure that what's under the root does not go negative. So x cannot be negative. Since the smallest value of x is 0 (because of the domain), then the range's minimum value will happen when x is 0. (So plug in 0 for x, and see what y is). The upper limit of the function will go on forever.
 2 years ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
You got it, that's the minimum of the range. As x gets bigger and bigger, there is no limit, it just grows and grows forever.
 2 years ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
so.. [17,infinity) ?
 2 years ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
That is your range, yes.
 2 years ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
how do I find the domain with this function?
 2 years ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
(inf,inf) ?
 2 years ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
Well, as we talked about earlier, the domain would be anything that is a "no no". You have a square root, and here, you cannot take the square root of a negative number, as it has no real solutions.
 2 years ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
anything that is NOT a "nono", sorry ;]
 2 years ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
No, you simply have sqrt(x), since you cannot take the square root of a negative number, we know that x MUST be greater than or equal to 0.
 2 years ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
dw:1346014535907:dw
 2 years ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
We're looking for x's that might make the equation undefined. That's what it means to find the domain. The only thing in this equation that can become undefined (or have no real solutions) is the square root. Which can't be negative.
 2 years ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
so x is all real numbers that are positive then?
 2 years ago

qpHalcy0n Group TitleBest ResponseYou've already chosen the best response.1
Yep, or in other words x >= 0
 2 years ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
how do I put that into interval notation though? [0,inf)
 2 years ago
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