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It's also okay to express the inequalities for x in terms of y, seeing as this is a type II region.

count me out

x_0 is a point,
x_1 - x_2 is a distance

@experimentX x_0, x_1, x_2, y_1, y_2 are all scalars

okay, I guess I'm going to Math.SE again!

what do you mean? you have to find the area of the region

i thought you had to define the region with inequalities... a

why not use piece wise functions ??

|dw:1346028684685:dw|
the region in middle is defined as
e < x < f
b < y < c

That's a rectangle

hmm...looks like i am no help :|

My suggestion would be to try polar although that has not given me any success so far.

we can assume the region is symmetric about x-axis correct ?

yes.

We know for a fact even

yes thats what I said you could do. But we'll see what SE says. I'll post the link soon.

you sir, are the best

http://math.stackexchange.com/questions/187316/how-can-i-define-the-area-between-two-ellipses