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hawkfalcon
 3 years ago
Another lim problem, but different:(
hawkfalcon
 3 years ago
Another lim problem, but different:(

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hawkfalcon
 3 years ago
Best ResponseYou've already chosen the best response.1\[f(x) = \left[\begin{matrix}x^21 & x<1 \\ 4x & x>=1\end{matrix}\right]\]

hawkfalcon
 3 years ago
Best ResponseYou've already chosen the best response.1I can do the lim, but how do i do it on that:O it lin x>1

hawkfalcon
 3 years ago
Best ResponseYou've already chosen the best response.1\[\lim_{x \rightarrow 1}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1346015959313:dw Your graph will look something like this

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What is the limit for the function x^2  1 as it approaches 1?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hmm, not quite. You want to approach x = 1.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Follow the graph of x^2 1 as it approaches x =1. What is the yvalue?

hawkfalcon
 3 years ago
Best ResponseYou've already chosen the best response.1Sorry *.* i'm not very good a limits:(

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes :) then follow the graph of 4x as it approaches x=1. You start from the right hand side and move back till you reach x=1.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What would you say the limit was for that equation?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok, are the two limits for both equations the same?

hawkfalcon
 3 years ago
Best ResponseYou've already chosen the best response.1Nope. Oh:3. Dur dur. You compare the 2 equations:3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What is your final answer for the problem?

hawkfalcon
 3 years ago
Best ResponseYou've already chosen the best response.1@Denebel one last Q. It also says to find x>+ and . In this cast, thats DNE too. right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Nope, as x>+ means when x approaches a number (in this case, 1) from the right hand side. x> means when x approaches (1) from the left hand side.

hawkfalcon
 3 years ago
Best ResponseYou've already chosen the best response.1But those are not the same for either left or right.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You only need to make sure they are the same when they don't give you a +/ Since the next part of the problem asks you to state the limit when it comes from +, then when it comes from  you say what you told me before. So when x> 1+ is when it approaches x=1 from the right side. You only look at the function 4x in this case. x> 1 is when it approaches x=1 from the left side, so look at the function x^2  1

hawkfalcon
 3 years ago
Best ResponseYou've already chosen the best response.1Oh so you only look at each problem separately then :O

hawkfalcon
 3 years ago
Best ResponseYou've already chosen the best response.1so lim x>1 = 0 and + = 3 and x> = DNE

hawkfalcon
 3 years ago
Best ResponseYou've already chosen the best response.1<3 Thank you so much!
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