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\[f(x) = \left[\begin{matrix}x^2-1 & x<1 \\ 4-x & x>=1\end{matrix}\right]\]

I can do the lim, but how do i do it on that:O
it lin x->1

\[\lim_{x \rightarrow 1}\]

|dw:1346015959313:dw|
Your graph will look something like this

What is the limit for the function x^2 - 1 as it approaches 1?

Erm. -inf. right?

Hmm, not quite. You want to approach x = 1.

Follow the graph of x^2 -1 as it approaches x =1. What is the y-value?

I think:3

Sorry *.* i'm not very good a limits:(

What would you say the limit was for that equation?

Ok, are the two limits for both equations the same?

Nope. Oh:3. Dur dur. You compare the 2 equations:3

What is your final answer for the problem?

DNE

@Denebel one last Q. It also says to find x->+ and -. In this cast, thats DNE too. right?

But those are not the same for either left or right.

Oh so you only look at each problem separately then :O

so lim x->1- = 0 and + = 3 and x-> = DNE

Yup.

<3 Thank you so much!