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hawkfalcon Group Title

Another lim problem, but different:(

  • 2 years ago
  • 2 years ago

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  1. hawkfalcon Group Title
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    \[f(x) = \left[\begin{matrix}x^2-1 & x<1 \\ 4-x & x>=1\end{matrix}\right]\]

    • 2 years ago
  2. hawkfalcon Group Title
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    I can do the lim, but how do i do it on that:O it lin x->1

    • 2 years ago
  3. hawkfalcon Group Title
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    \[\lim_{x \rightarrow 1}\]

    • 2 years ago
  4. Denebel Group Title
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    |dw:1346015959313:dw| Your graph will look something like this

    • 2 years ago
  5. Denebel Group Title
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    What is the limit for the function x^2 - 1 as it approaches 1?

    • 2 years ago
  6. hawkfalcon Group Title
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    Erm. -inf. right?

    • 2 years ago
  7. Denebel Group Title
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    Hmm, not quite. You want to approach x = 1.

    • 2 years ago
  8. Denebel Group Title
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    Follow the graph of x^2 -1 as it approaches x =1. What is the y-value?

    • 2 years ago
  9. hawkfalcon Group Title
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    0

    • 2 years ago
  10. hawkfalcon Group Title
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    I think:3

    • 2 years ago
  11. hawkfalcon Group Title
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    Sorry *.* i'm not very good a limits:(

    • 2 years ago
  12. Denebel Group Title
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    Yes :) then follow the graph of 4-x as it approaches x=1. You start from the right hand side and move back till you reach x=1.

    • 2 years ago
  13. Denebel Group Title
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    What would you say the limit was for that equation?

    • 2 years ago
  14. hawkfalcon Group Title
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    3

    • 2 years ago
  15. Denebel Group Title
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    Ok, are the two limits for both equations the same?

    • 2 years ago
  16. hawkfalcon Group Title
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    Nope. Oh:3. Dur dur. You compare the 2 equations:3

    • 2 years ago
  17. Denebel Group Title
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    What is your final answer for the problem?

    • 2 years ago
  18. hawkfalcon Group Title
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    DNE

    • 2 years ago
  19. hawkfalcon Group Title
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    @Denebel one last Q. It also says to find x->+ and -. In this cast, thats DNE too. right?

    • 2 years ago
  20. Denebel Group Title
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    Nope, as x->+ means when x approaches a number (in this case, 1) from the right hand side. x->- means when x approaches (1) from the left hand side.

    • 2 years ago
  21. hawkfalcon Group Title
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    But those are not the same for either left or right.

    • 2 years ago
  22. Denebel Group Title
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    You only need to make sure they are the same when they don't give you a +/- Since the next part of the problem asks you to state the limit when it comes from +, then when it comes from - you say what you told me before. So when x-> 1+ is when it approaches x=1 from the right side. You only look at the function 4-x in this case. x-> 1- is when it approaches x=1 from the left side, so look at the function x^2 - 1

    • 2 years ago
  23. hawkfalcon Group Title
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    Oh so you only look at each problem separately then :O

    • 2 years ago
  24. hawkfalcon Group Title
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    so lim x->1- = 0 and + = 3 and x-> = DNE

    • 2 years ago
  25. Denebel Group Title
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    Yup.

    • 2 years ago
  26. hawkfalcon Group Title
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    <3 Thank you so much!

    • 2 years ago
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