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hawkfalcon

  • 3 years ago

Evaluate for m and evaluate the equation

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  1. hawkfalcon
    • 3 years ago
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    let \[x1=6, x2=8,x3=9, x4=13. Evaluate m=\sum_{i=1}^{4}x1\]

  2. hawkfalcon
    • 3 years ago
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    Then use the values of x1, x2, x3, x4, and m to evaluate \[\frac{ \sum_{i=1}^{4}(x1=m)^2 }{4 }\]

  3. hawkfalcon
    • 3 years ago
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    Noone?:(

  4. eseidl
    • 3 years ago
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    Isn't the first equation just telling you to add up x1, x2, x3 and x4...or am I missing something?

  5. hawkfalcon
    • 3 years ago
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    no, xsubscript 1

  6. Mikael
    • 3 years ago
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    Hi there, the first just asks you their sum

  7. hawkfalcon
    • 3 years ago
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    Wait what seriously?

  8. hawkfalcon
    • 3 years ago
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    The e thingy with the i = 1 is saying add them up?

  9. Mikael
    • 3 years ago
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    You simply mis-read

  10. eseidl
    • 3 years ago
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    yep

  11. hawkfalcon
    • 3 years ago
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    o.O

  12. Mikael
    • 3 years ago
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    the "thingy" is subscript i (small hard to read ;) )

  13. eseidl
    • 3 years ago
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    just add them. I think the equation should read:\[\sum_{i=1}^{4}x_i\]

  14. eseidl
    • 3 years ago
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    where m is the sum.

  15. eseidl
    • 3 years ago
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    The second equation asks you to take the sum of the squares of x1, x2, x3 and x4

  16. eseidl
    • 3 years ago
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    and then divide by four :)

  17. hawkfalcon
    • 3 years ago
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    sorry, i couldn't connect. It is a 1, not an i.

  18. hawkfalcon
    • 3 years ago
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    @Mikael

  19. eseidl
    • 3 years ago
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    Well, that is kind of a strange question. Because, if x1=6, then\[\sum_{i=1}^{4}6=4(6)=24\]

  20. eseidl
    • 3 years ago
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    Similarly,\[\frac{\sum_{i=1}^{4}(6)^2}{4}=\frac{4(36)}{4}=36\]

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