Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

sammy5592

  • 2 years ago

Part 1: Solve the following system of equations. Please show your work to receive full credit. x - y = 10 2x + y = 2 Part 2: Explain which method you chose to solve the system and why you felt it was the best choice.

  • This Question is Closed
  1. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Add those two equations first and tell me what u get?

  2. Mellissa
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    combine like terms first

  3. sammy5592
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    3x+y=12

  4. Mellissa
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is that Part 2 part of the equation ?@Sammy5592

  5. sammy5592
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no @Mellissa

  6. shaik0124
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1346076054334:dw|

  7. Mellissa
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok @Sammy

  8. shaik0124
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    -3y=18 y=-6 x-(-6)=10 x+6=10 x=10-6 x=4

  9. shaik0124
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    therefore x=4,y=-6 is answer

  10. sammy5592
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can u write the firsrt 1 out like that

  11. hartnn
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @sammy5592 how did u get 3x+y=12 u should get 3x=12 check again.

  12. shaik0124
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    i multiplied first equation by 2 then subtracted from 2nd equation ..this gives y .put y value in any one of the equations u will get x,theefore x,y u got is solution

  13. sammy5592
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no i mean how you did the second equation

  14. shaik0124
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    did u got @sammy5592

  15. sammy5592
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ???

  16. shaik0124
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    did u understand the solution i replied for above problem

  17. sammy5592
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  18. sammy5592
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    part 2 ???

  19. shaik0124
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it is substitution method

  20. shaik0124
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it is best bcoz if u find 1 value then automatically it is easy to find another value

  21. sammy5592
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thanks :)

  22. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.