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abayomi12 Group TitleBest ResponseYou've already chosen the best response.0
Indirect proof means assume the opposite and find a contradiction. If a + c > b + c then a > b
 one year ago

abayomi12 Group TitleBest ResponseYou've already chosen the best response.0
assume that a < b Then there exists a positive number such that a+X = b Now, plug this value into the first part... a + c > (a+X) + c So (a + c) > (a + c) + X So, a number PLUS a positive number is less than the number itself? This is a contradiction. So it is not the case that a < b Part 2: assume a = b a + c > a + c No number (a+c) can be greater than itself, so this is a contradiction. So, it is not the case that a = b So, a is not <= b So a > b By the way, it doesn't matter if a, b or c = 0, the simply can't equal each other.
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
why these answers get more and more random as the day goes on
 one year ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
\[ \large A\setminus(B\cup C)=A\cap(B\cup C)^c =A\cap(B^c\cap C^c) \] \[ \large A\cap A\cap B^c\cap C^c=(A\cap B^c)\cap(A\cap C^c)= \]
 one year ago
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