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KNicksfan4life Group Title

32. If 0 < n < 1, which of the following gives the correct ordering of n,n,and n2? (A) n < n < n2 (D)n<n2 < n (B) n < n2 < n (C) n < n < n2 (E) n2 <n< n

  • one year ago
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  1. KNicksfan4life Group Title
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    look at question 32

    • one year ago
  2. satellite73 Group Title
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    here is a trick if you get confused since you are not given numbers, clearly it doesn't matter what they are. so pick one, find the answer, and it will be right no matter what

    • one year ago
  3. KNicksfan4life Group Title
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    i dont get it

    • one year ago
  4. satellite73 Group Title
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    i pick \(n=\frac{1}{4}\) so \(n^2=\left(\frac{1}{4}\right)^2=\frac{1}{16}\) and \(\sqrt{n}=\sqrt{\frac{1}{4}}=\frac{1}{2}\)

    • one year ago
  5. satellite73 Group Title
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    now we order them, and whatever answer we get will be the right one this is a good trick to know for standardized tests

    • one year ago
  6. satellite73 Group Title
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    i get \[\frac{1}{16}<\frac{1}{4}<\frac{1}{2}\] so \[n^2<n<\sqrt{n}\] must be correct

    • one year ago
  7. satellite73 Group Title
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    btw i picked \(\frac{1}{4}\) because it was easy to take the square root

    • one year ago
  8. KNicksfan4life Group Title
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    so it's E

    • one year ago
  9. satellite73 Group Title
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    i didn't look at the answers

    • one year ago
  10. KNicksfan4life Group Title
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    ok

    • one year ago
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