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KNicksfan4life

  • 2 years ago

32. If 0 < n < 1, which of the following gives the correct ordering of n,n,and n2? (A) n < n < n2 (D)n<n2 < n (B) n < n2 < n (C) n < n < n2 (E) n2 <n< n

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  1. KNicksfan4life
    • 2 years ago
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    look at question 32

  2. satellite73
    • 2 years ago
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    here is a trick if you get confused since you are not given numbers, clearly it doesn't matter what they are. so pick one, find the answer, and it will be right no matter what

  3. KNicksfan4life
    • 2 years ago
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    i dont get it

  4. satellite73
    • 2 years ago
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    i pick \(n=\frac{1}{4}\) so \(n^2=\left(\frac{1}{4}\right)^2=\frac{1}{16}\) and \(\sqrt{n}=\sqrt{\frac{1}{4}}=\frac{1}{2}\)

  5. satellite73
    • 2 years ago
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    now we order them, and whatever answer we get will be the right one this is a good trick to know for standardized tests

  6. satellite73
    • 2 years ago
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    i get \[\frac{1}{16}<\frac{1}{4}<\frac{1}{2}\] so \[n^2<n<\sqrt{n}\] must be correct

  7. satellite73
    • 2 years ago
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    btw i picked \(\frac{1}{4}\) because it was easy to take the square root

  8. KNicksfan4life
    • 2 years ago
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    so it's E

  9. satellite73
    • 2 years ago
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    i didn't look at the answers

  10. KNicksfan4life
    • 2 years ago
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    ok

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