## anonymous 3 years ago 32. If 0 < n < 1, which of the following gives the correct ordering of n,n,and n2? (A) n < n < n2 (D)n<n2 < n (B) n < n2 < n (C) n < n < n2 (E) n2 <n< n

1. anonymous

look at question 32

2. anonymous

here is a trick if you get confused since you are not given numbers, clearly it doesn't matter what they are. so pick one, find the answer, and it will be right no matter what

3. anonymous

i dont get it

4. anonymous

i pick $$n=\frac{1}{4}$$ so $$n^2=\left(\frac{1}{4}\right)^2=\frac{1}{16}$$ and $$\sqrt{n}=\sqrt{\frac{1}{4}}=\frac{1}{2}$$

5. anonymous

now we order them, and whatever answer we get will be the right one this is a good trick to know for standardized tests

6. anonymous

i get $\frac{1}{16}<\frac{1}{4}<\frac{1}{2}$ so $n^2<n<\sqrt{n}$ must be correct

7. anonymous

btw i picked $$\frac{1}{4}$$ because it was easy to take the square root

8. anonymous

so it's E

9. anonymous

i didn't look at the answers

10. anonymous

ok