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KNicksfan4life Group Title

32. If 0 < n < 1, which of the following gives the correct ordering of n,n,and n2? (A) n < n < n2 (D)n<n2 < n (B) n < n2 < n (C) n < n < n2 (E) n2 <n< n

  • 2 years ago
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  1. KNicksfan4life Group Title
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    look at question 32

    • 2 years ago
  2. satellite73 Group Title
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    here is a trick if you get confused since you are not given numbers, clearly it doesn't matter what they are. so pick one, find the answer, and it will be right no matter what

    • 2 years ago
  3. KNicksfan4life Group Title
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    i dont get it

    • 2 years ago
  4. satellite73 Group Title
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    i pick \(n=\frac{1}{4}\) so \(n^2=\left(\frac{1}{4}\right)^2=\frac{1}{16}\) and \(\sqrt{n}=\sqrt{\frac{1}{4}}=\frac{1}{2}\)

    • 2 years ago
  5. satellite73 Group Title
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    now we order them, and whatever answer we get will be the right one this is a good trick to know for standardized tests

    • 2 years ago
  6. satellite73 Group Title
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    i get \[\frac{1}{16}<\frac{1}{4}<\frac{1}{2}\] so \[n^2<n<\sqrt{n}\] must be correct

    • 2 years ago
  7. satellite73 Group Title
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    btw i picked \(\frac{1}{4}\) because it was easy to take the square root

    • 2 years ago
  8. KNicksfan4life Group Title
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    so it's E

    • 2 years ago
  9. satellite73 Group Title
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    i didn't look at the answers

    • 2 years ago
  10. KNicksfan4life Group Title
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    ok

    • 2 years ago
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