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12. In the figure above, XYZ is equilateral, with side of length 2. If WY is a diameter of the circle with center O, then the area of the circle is (A) √3π/4 (B)2π/3 (C)3π/4 (D) π (E) 3π/2

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look at question 12
\[ YZ = 2\]\[WZ= \frac{side length}{2} = \frac{2}{2} = 1\]Now use Pythagoras theorem in triangle YWZ to find YW. According to the figure, you can see that \[YW = 2\times radius\]So once you have YW, you can find the radius and then the area of the circle using\[Area = \pi\times radius^2\]
i dont get it can u please just tell me the answer

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