## KNicksfan4life 2 years ago 12. In the figure above, XYZ is equilateral, with side of length 2. If WY is a diameter of the circle with center O, then the area of the circle is (A) √3π/4 (B)2π/3 (C)3π/4 (D) π (E) 3π/2

1. KNicksfan4life

look at question 12

2. akitav

$YZ = 2$$WZ= \frac{side length}{2} = \frac{2}{2} = 1$Now use Pythagoras theorem in triangle YWZ to find YW. According to the figure, you can see that $YW = 2\times radius$So once you have YW, you can find the radius and then the area of the circle using$Area = \pi\times radius^2$

3. KNicksfan4life

i dont get it can u please just tell me the answer

4. akitav

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