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Question on Simplifying Boolean expression (Logic Gates) Q1) ABC + AB(bar)C + ABC(bar) ---Here I'm getting the answer AB + AC -Is that Right??? Q2) AB + A(bar)C + BC (bar) -> Line above the letter. Also called Dash sometimes.

Mathematics
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Q1 is like above ?
last bar is only for C, or for whole ABC ?

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Other answers:

Last bar is only for C. Any yes it is as U've shown.
okay lets see...
Please do. I'm seriously stumped. (For the second one- The 1st one atleast i got something)
first one is correct :
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Q2 is like above ,right ?
Nope. Its AB + A'C + BC. A' as In A(bar)
Thats wat stumped me as i couldn't really find anything to take common and continue forth. :(
okay just a sec.. let me get a paper !
answer should simplify to : A'C + AB im trying to work backwards...
ah its simple friend...
AB + A'C + BC AB + A'C + BC(A + A')
Ok.
AB + A'C + ABC + A'BC
group 1st & 3rd terms
2nd & last terms
Wait since u said U are trying to solve it backwards, does that mean u found the answer somewhere? U get AB(1+C)+(1+B)A'C
since, 1+x = 1
it simplifies to AB + A'C
i simplified it using karnaugh-map quickly.... and worked backwards hehe
Thanku very much. FOrgot about that Identity. :) Yes I guess i understood now. :) -Closing thread. :)
glad to hear :) yw !!!
Just an FYI, I was stumped bby thihs for quite some time now. U helped me alot. :D
np :D

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