## Tri_Edge_1836 3 years ago Question on Simplifying Boolean expression (Logic Gates) Q1) ABC + AB(bar)C + ABC(bar) ---Here I'm getting the answer AB + AC -Is that Right??? Q2) AB + A(bar)C + BC (bar) -> Line above the letter. Also called Dash sometimes.

1. ganeshie8

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2. ganeshie8

Q1 is like above ?

3. ganeshie8

last bar is only for C, or for whole ABC ?

4. Tri_Edge_1836

Last bar is only for C. Any yes it is as U've shown.

5. ganeshie8

okay lets see...

6. Tri_Edge_1836

Please do. I'm seriously stumped. (For the second one- The 1st one atleast i got something)

7. ganeshie8

first one is correct :

8. ganeshie8

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9. ganeshie8

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10. ganeshie8

Q2 is like above ,right ?

11. Tri_Edge_1836

Nope. Its AB + A'C + BC. A' as In A(bar)

12. Tri_Edge_1836

Thats wat stumped me as i couldn't really find anything to take common and continue forth. :(

13. ganeshie8

okay just a sec.. let me get a paper !

14. ganeshie8

answer should simplify to : A'C + AB im trying to work backwards...

15. ganeshie8

ah its simple friend...

16. ganeshie8

AB + A'C + BC AB + A'C + BC(A + A')

17. Tri_Edge_1836

Ok.

18. ganeshie8

AB + A'C + ABC + A'BC

19. ganeshie8

group 1st & 3rd terms

20. ganeshie8

2nd & last terms

21. Tri_Edge_1836

Wait since u said U are trying to solve it backwards, does that mean u found the answer somewhere? U get AB(1+C)+(1+B)A'C

22. ganeshie8

since, 1+x = 1

23. ganeshie8

it simplifies to AB + A'C

24. ganeshie8

i simplified it using karnaugh-map quickly.... and worked backwards hehe

25. Tri_Edge_1836

Thanku very much. FOrgot about that Identity. :) Yes I guess i understood now. :) -Closing thread. :)

26. ganeshie8

glad to hear :) yw !!!

27. Tri_Edge_1836

Just an FYI, I was stumped bby thihs for quite some time now. U helped me alot. :D

28. ganeshie8

np :D