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hdismuke149

  • 3 years ago

How do you solve an equation by completing the square?

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  1. swin2013
    • 3 years ago
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    An example would be: (x – 4)2 = 5 x – 4 = ± sqrt(5) x = 4 ± sqrt(5) x = 4 – sqrt(5) and x = 4 + sqrt(5)

  2. hdismuke149
    • 3 years ago
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    I'm sorry, I still don't understand. Could you show me how to do it with an equation like x^2+6x=7

  3. swin2013
    • 3 years ago
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    Take half of the x term (6x) and square it. Make sure you are aware of the sign. So it'll be +9 since 6/2 = 3 and (3)^2 is 9.

  4. swin2013
    • 3 years ago
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    Then it should look like x^2 +6x +9 = 7+9

  5. swin2013
    • 3 years ago
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    Now it is the complete the square part. You take half of the x term again to make it look like (x+3x)^2 and add the other side. So the new equation will look like (x+3)^2 = 16. To find the solutions, you must get rid of the squared (x+3) on the left side by square rooting both sides. It will look like x+3 = + or - 4. Now move the 3 over to the right side to find your solutions. it will be -3 +4 or -3 -4 which is 1 and -7

  6. hdismuke149
    • 3 years ago
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    Thank You!!

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