anonymous
  • anonymous
solve the diff equation. (y^-1)dy + (y*e^cos(x))*(sin(x))dx
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Equals zero?
anonymous
  • anonymous
yes ... =0
anonymous
  • anonymous
Thanks

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anonymous
  • anonymous
It looks separable to me.
anonymous
  • anonymous
i got it to \[- e ^{\cos(x)} = y^{-1} +C\] is this correct first off?
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
i cannot figure out how to solve for y
anonymous
  • anonymous
Put the arbitrary constant on the other side. It is arbitrary, so it doesn't matter which side of the equation it is on.
anonymous
  • anonymous
Does that make sense?
anonymous
  • anonymous
but it is y^-1
anonymous
  • anonymous
Well, if we have\[y^{-1}=C-e^{\cos(x)}\]We can simply take the reciprocal of both sides, provided that it doesn't equal zero:\[y=\frac{1}{C-e^{\cos(x)}}\]
anonymous
  • anonymous
alright thanks that's the answer.. couldn't figure out how to change it but it makes sense

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