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EulerGroupieBest ResponseYou've already chosen the best response.0
It looks separable to me.
 one year ago

haganmcBest ResponseYou've already chosen the best response.0
i got it to \[ e ^{\cos(x)} = y^{1} +C\] is this correct first off?
 one year ago

haganmcBest ResponseYou've already chosen the best response.0
i cannot figure out how to solve for y
 one year ago

Herp_DerpBest ResponseYou've already chosen the best response.1
Put the arbitrary constant on the other side. It is arbitrary, so it doesn't matter which side of the equation it is on.
 one year ago

Herp_DerpBest ResponseYou've already chosen the best response.1
Does that make sense?
 one year ago

Herp_DerpBest ResponseYou've already chosen the best response.1
Well, if we have\[y^{1}=Ce^{\cos(x)}\]We can simply take the reciprocal of both sides, provided that it doesn't equal zero:\[y=\frac{1}{Ce^{\cos(x)}}\]
 one year ago

haganmcBest ResponseYou've already chosen the best response.0
alright thanks that's the answer.. couldn't figure out how to change it but it makes sense
 one year ago
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