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EulerGroupie
 2 years ago
Best ResponseYou've already chosen the best response.0It looks separable to me.

haganmc
 2 years ago
Best ResponseYou've already chosen the best response.0i got it to \[ e ^{\cos(x)} = y^{1} +C\] is this correct first off?

haganmc
 2 years ago
Best ResponseYou've already chosen the best response.0i cannot figure out how to solve for y

Herp_Derp
 2 years ago
Best ResponseYou've already chosen the best response.1Put the arbitrary constant on the other side. It is arbitrary, so it doesn't matter which side of the equation it is on.

Herp_Derp
 2 years ago
Best ResponseYou've already chosen the best response.1Does that make sense?

Herp_Derp
 2 years ago
Best ResponseYou've already chosen the best response.1Well, if we have\[y^{1}=Ce^{\cos(x)}\]We can simply take the reciprocal of both sides, provided that it doesn't equal zero:\[y=\frac{1}{Ce^{\cos(x)}}\]

haganmc
 2 years ago
Best ResponseYou've already chosen the best response.0alright thanks that's the answer.. couldn't figure out how to change it but it makes sense
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