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haganmc

solve the diff equation. (y^-1)dy + (y*e^cos(x))*(sin(x))dx

  • one year ago
  • one year ago

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  1. Herp_Derp
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    Equals zero?

    • one year ago
  2. haganmc
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    yes ... =0

    • one year ago
  3. Herp_Derp
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    Thanks

    • one year ago
  4. EulerGroupie
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    It looks separable to me.

    • one year ago
  5. haganmc
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    i got it to \[- e ^{\cos(x)} = y^{-1} +C\] is this correct first off?

    • one year ago
  6. Herp_Derp
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    Yes.

    • one year ago
  7. haganmc
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    i cannot figure out how to solve for y

    • one year ago
  8. Herp_Derp
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    Put the arbitrary constant on the other side. It is arbitrary, so it doesn't matter which side of the equation it is on.

    • one year ago
  9. Herp_Derp
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    Does that make sense?

    • one year ago
  10. haganmc
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    but it is y^-1

    • one year ago
  11. Herp_Derp
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    Well, if we have\[y^{-1}=C-e^{\cos(x)}\]We can simply take the reciprocal of both sides, provided that it doesn't equal zero:\[y=\frac{1}{C-e^{\cos(x)}}\]

    • one year ago
  12. haganmc
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    alright thanks that's the answer.. couldn't figure out how to change it but it makes sense

    • one year ago
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