anonymous
  • anonymous
Solve: x2 - 20x + 36 = 0
Mathematics
schrodinger
  • schrodinger
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Callisto
  • Callisto
x^2 - 20x +36 = 0 x^2 -2x - 18x +36 = 0 x(x-2) -18(x-2) = 0 (x-2)(x-18) = 0 x-2 = 0 or x-18 = 0 <-solve these equations
MathLegend
  • MathLegend
Shouldn't you have walked her through from the beginning?
Callisto
  • Callisto
To solve quadratic equations, you can do it like the above, that is factoring the expression on the left, put each factor = 0 and solve them OR Use quadratic formula.

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MathLegend
  • MathLegend
You basically just gave out the answer.
Callisto
  • Callisto
@MathLegend Did I? Where's the answer?
MathLegend
  • MathLegend
I said you basically did if you can read.
Callisto
  • Callisto
The only mistake that I made here was not explain with words But basically, I did show the asker the way to work the answer out.
MathLegend
  • MathLegend
Yes, but my point is.. since she posted this. Don't you think she may need some explanation along the way?
MathLegend
  • MathLegend
Liek as you go from Step 1 to Step 2
MathLegend
  • MathLegend
Like*
Callisto
  • Callisto
If that's what you want, x^2 - 20x +36 = 0 Split the middle term so that you can factor the expression easier x^2 -2x - 18x +36 = 0 Take out the common factor for the first two terms and last two terms x(x-2) -18(x-2) = 0 Take out the common factor again (x-2)(x-18) = 0 Put each factor = 0 x-2 = 0 or x-18 = 0 solve these equations on your own
MathLegend
  • MathLegend
Okay, I am just saying because a Mod told me that when I first joined.
Callisto
  • Callisto
I'm sorry but I still don't think I'm giving the answer.
MathLegend
  • MathLegend
Okay. :)
anonymous
  • anonymous
@Ghatiii, did you get your answers?
anonymous
  • anonymous
Or.....Do u knw Quadratic Formuld..)) it will be very easy
Callisto
  • Callisto
Just want to make few points clear. 1. If I was giving answer in the first post, I'm still giving answer in the second time I did it, even with explanations. 2. I didn't intend to give answers, as always. 3. I understand that I should have explained using words, but without using a word doesn't mean that I give answer. At least, I leave some steps for the asker to do it. 4. If you have noticed since I've started typing in this post. After I left the first comment, I actually kept typing again as I found it is better to leave some words to the asker that I'm doing factorization, as you've seen above. I apologize that I didn't explain what I had done in the first post, but I still insist that I'm not giving answers.
anonymous
  • anonymous
|dw:1346139489935:dw|
anonymous
  • anonymous
\[x = \frac{ -b \pm \sqrt{b ^{2} - 4ac} }{ 2a }\]
anonymous
  • anonymous
Where a is coefficient of x^2 b is coefficient of x and c is the constant.
anonymous
  • anonymous
I would've just given the quadratic equation and left it at that but I think your reply was just fine. I thought it was good of you to add the explanation afterwards.
lgbasallote
  • lgbasallote
i think what mathlegend was saying is not about the "annotations" but the "lack of interaction"

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