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anonymous
 4 years ago
Solve: x2  20x + 36 = 0
anonymous
 4 years ago
Solve: x2  20x + 36 = 0

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Callisto
 4 years ago
Best ResponseYou've already chosen the best response.3x^2  20x +36 = 0 x^2 2x  18x +36 = 0 x(x2) 18(x2) = 0 (x2)(x18) = 0 x2 = 0 or x18 = 0 <solve these equations

MathLegend
 4 years ago
Best ResponseYou've already chosen the best response.1Shouldn't you have walked her through from the beginning?

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.3To solve quadratic equations, you can do it like the above, that is factoring the expression on the left, put each factor = 0 and solve them OR Use quadratic formula.

MathLegend
 4 years ago
Best ResponseYou've already chosen the best response.1You basically just gave out the answer.

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.3@MathLegend Did I? Where's the answer?

MathLegend
 4 years ago
Best ResponseYou've already chosen the best response.1I said you basically did if you can read.

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.3The only mistake that I made here was not explain with words But basically, I did show the asker the way to work the answer out.

MathLegend
 4 years ago
Best ResponseYou've already chosen the best response.1Yes, but my point is.. since she posted this. Don't you think she may need some explanation along the way?

MathLegend
 4 years ago
Best ResponseYou've already chosen the best response.1Liek as you go from Step 1 to Step 2

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.3If that's what you want, x^2  20x +36 = 0 Split the middle term so that you can factor the expression easier x^2 2x  18x +36 = 0 Take out the common factor for the first two terms and last two terms x(x2) 18(x2) = 0 Take out the common factor again (x2)(x18) = 0 Put each factor = 0 x2 = 0 or x18 = 0 solve these equations on your own

MathLegend
 4 years ago
Best ResponseYou've already chosen the best response.1Okay, I am just saying because a Mod told me that when I first joined.

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.3I'm sorry but I still don't think I'm giving the answer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Ghatiii, did you get your answers?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Or.....Do u knw Quadratic Formuld..)) it will be very easy

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.3Just want to make few points clear. 1. If I was giving answer in the first post, I'm still giving answer in the second time I did it, even with explanations. 2. I didn't intend to give answers, as always. 3. I understand that I should have explained using words, but without using a word doesn't mean that I give answer. At least, I leave some steps for the asker to do it. 4. If you have noticed since I've started typing in this post. After I left the first comment, I actually kept typing again as I found it is better to leave some words to the asker that I'm doing factorization, as you've seen above. I apologize that I didn't explain what I had done in the first post, but I still insist that I'm not giving answers.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1346139489935:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x = \frac{ b \pm \sqrt{b ^{2}  4ac} }{ 2a }\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Where a is coefficient of x^2 b is coefficient of x and c is the constant.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I would've just given the quadratic equation and left it at that but I think your reply was just fine. I thought it was good of you to add the explanation afterwards.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think what mathlegend was saying is not about the "annotations" but the "lack of interaction"
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