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CallistoBest ResponseYou've already chosen the best response.3
x^2  20x +36 = 0 x^2 2x  18x +36 = 0 x(x2) 18(x2) = 0 (x2)(x18) = 0 x2 = 0 or x18 = 0 <solve these equations
 one year ago

MathLegendBest ResponseYou've already chosen the best response.1
Shouldn't you have walked her through from the beginning?
 one year ago

CallistoBest ResponseYou've already chosen the best response.3
To solve quadratic equations, you can do it like the above, that is factoring the expression on the left, put each factor = 0 and solve them OR Use quadratic formula.
 one year ago

MathLegendBest ResponseYou've already chosen the best response.1
You basically just gave out the answer.
 one year ago

CallistoBest ResponseYou've already chosen the best response.3
@MathLegend Did I? Where's the answer?
 one year ago

MathLegendBest ResponseYou've already chosen the best response.1
I said you basically did if you can read.
 one year ago

CallistoBest ResponseYou've already chosen the best response.3
The only mistake that I made here was not explain with words But basically, I did show the asker the way to work the answer out.
 one year ago

MathLegendBest ResponseYou've already chosen the best response.1
Yes, but my point is.. since she posted this. Don't you think she may need some explanation along the way?
 one year ago

MathLegendBest ResponseYou've already chosen the best response.1
Liek as you go from Step 1 to Step 2
 one year ago

CallistoBest ResponseYou've already chosen the best response.3
If that's what you want, x^2  20x +36 = 0 Split the middle term so that you can factor the expression easier x^2 2x  18x +36 = 0 Take out the common factor for the first two terms and last two terms x(x2) 18(x2) = 0 Take out the common factor again (x2)(x18) = 0 Put each factor = 0 x2 = 0 or x18 = 0 solve these equations on your own
 one year ago

MathLegendBest ResponseYou've already chosen the best response.1
Okay, I am just saying because a Mod told me that when I first joined.
 one year ago

CallistoBest ResponseYou've already chosen the best response.3
I'm sorry but I still don't think I'm giving the answer.
 one year ago

monokerousBest ResponseYou've already chosen the best response.0
@Ghatiii, did you get your answers?
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
Or.....Do u knw Quadratic Formuld..)) it will be very easy
 one year ago

CallistoBest ResponseYou've already chosen the best response.3
Just want to make few points clear. 1. If I was giving answer in the first post, I'm still giving answer in the second time I did it, even with explanations. 2. I didn't intend to give answers, as always. 3. I understand that I should have explained using words, but without using a word doesn't mean that I give answer. At least, I leave some steps for the asker to do it. 4. If you have noticed since I've started typing in this post. After I left the first comment, I actually kept typing again as I found it is better to leave some words to the asker that I'm doing factorization, as you've seen above. I apologize that I didn't explain what I had done in the first post, but I still insist that I'm not giving answers.
 one year ago

pratu043Best ResponseYou've already chosen the best response.1
\[x = \frac{ b \pm \sqrt{b ^{2}  4ac} }{ 2a }\]
 one year ago

pratu043Best ResponseYou've already chosen the best response.1
Where a is coefficient of x^2 b is coefficient of x and c is the constant.
 one year ago

monokerousBest ResponseYou've already chosen the best response.0
I would've just given the quadratic equation and left it at that but I think your reply was just fine. I thought it was good of you to add the explanation afterwards.
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
i think what mathlegend was saying is not about the "annotations" but the "lack of interaction"
 one year ago
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