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Ghatiii Group Title

Solve: x2 - 20x + 36 = 0

  • 2 years ago
  • 2 years ago

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  1. Callisto Group Title
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    x^2 - 20x +36 = 0 x^2 -2x - 18x +36 = 0 x(x-2) -18(x-2) = 0 (x-2)(x-18) = 0 x-2 = 0 or x-18 = 0 <-solve these equations

    • 2 years ago
  2. MathLegend Group Title
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    Shouldn't you have walked her through from the beginning?

    • 2 years ago
  3. Callisto Group Title
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    To solve quadratic equations, you can do it like the above, that is factoring the expression on the left, put each factor = 0 and solve them OR Use quadratic formula.

    • 2 years ago
  4. MathLegend Group Title
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    You basically just gave out the answer.

    • 2 years ago
  5. Callisto Group Title
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    @MathLegend Did I? Where's the answer?

    • 2 years ago
  6. MathLegend Group Title
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    I said you basically did if you can read.

    • 2 years ago
  7. Callisto Group Title
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    The only mistake that I made here was not explain with words But basically, I did show the asker the way to work the answer out.

    • 2 years ago
  8. MathLegend Group Title
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    Yes, but my point is.. since she posted this. Don't you think she may need some explanation along the way?

    • 2 years ago
  9. MathLegend Group Title
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    Liek as you go from Step 1 to Step 2

    • 2 years ago
  10. MathLegend Group Title
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    Like*

    • 2 years ago
  11. Callisto Group Title
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    If that's what you want, x^2 - 20x +36 = 0 Split the middle term so that you can factor the expression easier x^2 -2x - 18x +36 = 0 Take out the common factor for the first two terms and last two terms x(x-2) -18(x-2) = 0 Take out the common factor again (x-2)(x-18) = 0 Put each factor = 0 x-2 = 0 or x-18 = 0 solve these equations on your own

    • 2 years ago
  12. MathLegend Group Title
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    Okay, I am just saying because a Mod told me that when I first joined.

    • 2 years ago
  13. Callisto Group Title
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    I'm sorry but I still don't think I'm giving the answer.

    • 2 years ago
  14. MathLegend Group Title
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    Okay. :)

    • 2 years ago
  15. monokerous Group Title
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    @Ghatiii, did you get your answers?

    • 2 years ago
  16. Yahoo! Group Title
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    Or.....Do u knw Quadratic Formuld..)) it will be very easy

    • 2 years ago
  17. Callisto Group Title
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    Just want to make few points clear. 1. If I was giving answer in the first post, I'm still giving answer in the second time I did it, even with explanations. 2. I didn't intend to give answers, as always. 3. I understand that I should have explained using words, but without using a word doesn't mean that I give answer. At least, I leave some steps for the asker to do it. 4. If you have noticed since I've started typing in this post. After I left the first comment, I actually kept typing again as I found it is better to leave some words to the asker that I'm doing factorization, as you've seen above. I apologize that I didn't explain what I had done in the first post, but I still insist that I'm not giving answers.

    • 2 years ago
  18. Yahoo! Group Title
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    |dw:1346139489935:dw|

    • 2 years ago
  19. pratu043 Group Title
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    \[x = \frac{ -b \pm \sqrt{b ^{2} - 4ac} }{ 2a }\]

    • 2 years ago
  20. pratu043 Group Title
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    Where a is coefficient of x^2 b is coefficient of x and c is the constant.

    • 2 years ago
  21. monokerous Group Title
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    I would've just given the quadratic equation and left it at that but I think your reply was just fine. I thought it was good of you to add the explanation afterwards.

    • 2 years ago
  22. lgbasallote Group Title
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    i think what mathlegend was saying is not about the "annotations" but the "lack of interaction"

    • 2 years ago
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