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pratu043
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A machine gun fires 25 g bullets at the rate of 600 bullets per minute with a speed of 200 m/s. Calculate the force required to keep the gun in position.
 one year ago
 one year ago
pratu043 Group Title
A machine gun fires 25 g bullets at the rate of 600 bullets per minute with a speed of 200 m/s. Calculate the force required to keep the gun in position.
 one year ago
 one year ago

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Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
600 bullets per minute = 600/60 = 10 bullets per second F = n * m * v = 10 * 200 * 25 * 10^3 = 2N
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
But force is rate of change of momentum right?
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
sorry F=50N
 one year ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
He gave you in fact Change of momentum/ per 1 sec
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
My calcu was wrong..))
 one year ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
I didn't get you @Mikael.
 one year ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
See he calculated for U how much Momentum is given to ALL the bullets flyingout in the period of 1 second . IT IS the change in momentum of the gun too  with a minus sign of course
 one year ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
dw:1346144826007:dw
 one year ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
impulse is the variation of momentum
 one year ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
think in one bullet
 one year ago

Rohangrr Group TitleBest ResponseYou've already chosen the best response.0
\[ ♬ \ Jack \ of \ Oz \ ♬ \ [your \ turn] \]
 one year ago

TheProf Group TitleBest ResponseYou've already chosen the best response.0
If the slowest rate of acceleration of a bullet is 0.1 seconds, then 0.025 x (200/0.1) [F = ma] = 50 N. So that would be the force from each fired bullet. We get the 0.1 second as the gun fires 10 rounds per second.
 one year ago

ghazi Group TitleBest ResponseYou've already chosen the best response.0
force exerted by each bullet is impulsive therefore...force exerted by each bullet is 5 N that is the force which should be maintained to keep gun stationary
 one year ago
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