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pratu043
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A machine gun fires 25 g bullets at the rate of 600 bullets per minute with a speed of 200 m/s. Calculate the force required to keep the gun in position.
 2 years ago
 2 years ago
pratu043 Group Title
A machine gun fires 25 g bullets at the rate of 600 bullets per minute with a speed of 200 m/s. Calculate the force required to keep the gun in position.
 2 years ago
 2 years ago

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Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
600 bullets per minute = 600/60 = 10 bullets per second F = n * m * v = 10 * 200 * 25 * 10^3 = 2N
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
But force is rate of change of momentum right?
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
He gave you in fact Change of momentum/ per 1 sec
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
My calcu was wrong..))
 2 years ago

pratu043 Group TitleBest ResponseYou've already chosen the best response.0
I didn't get you @Mikael.
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
See he calculated for U how much Momentum is given to ALL the bullets flyingout in the period of 1 second . IT IS the change in momentum of the gun too  with a minus sign of course
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
dw:1346144826007:dw
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
impulse is the variation of momentum
 2 years ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.0
think in one bullet
 2 years ago

Rohangrr Group TitleBest ResponseYou've already chosen the best response.0
\[ ♬ \ Jack \ of \ Oz \ ♬ \ [your \ turn] \]
 2 years ago

TheProf Group TitleBest ResponseYou've already chosen the best response.0
If the slowest rate of acceleration of a bullet is 0.1 seconds, then 0.025 x (200/0.1) [F = ma] = 50 N. So that would be the force from each fired bullet. We get the 0.1 second as the gun fires 10 rounds per second.
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.0
force exerted by each bullet is impulsive therefore...force exerted by each bullet is 5 N that is the force which should be maintained to keep gun stationary
 2 years ago
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