anonymous
  • anonymous
A machine gun fires 25 g bullets at the rate of 600 bullets per minute with a speed of 200 m/s. Calculate the force required to keep the gun in position.
Physics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
600 bullets per minute = 600/60 = 10 bullets per second F = n * m * v = 10 * 200 * 25 * 10^-3 = 2N
anonymous
  • anonymous
But force is rate of change of momentum right?
anonymous
  • anonymous
sorry F=50N

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anonymous
  • anonymous
He gave you in fact Change of momentum/ per 1 sec
anonymous
  • anonymous
My calcu was wrong..))
anonymous
  • anonymous
I didn't get you @Mikael.
anonymous
  • anonymous
See he calculated for U how much Momentum is given to ALL the bullets flying-out in the period of 1 second . IT IS the change in momentum of the gun too - with a minus sign of course
anonymous
  • anonymous
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anonymous
  • anonymous
impulse is the variation of momentum
anonymous
  • anonymous
think in one bullet
anonymous
  • anonymous
\[-- ♬ \ Jack \ of \ Oz \ ♬ \ [your \ turn] \]
anonymous
  • anonymous
If the slowest rate of acceleration of a bullet is 0.1 seconds, then 0.025 x (200/0.1) [F = ma] = 50 N. So that would be the force from each fired bullet. We get the 0.1 second as the gun fires 10 rounds per second.
ghazi
  • ghazi
force exerted by each bullet is impulsive therefore...force exerted by each bullet is 5 N that is the force which should be maintained to keep gun stationary

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