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pratu043

  • 2 years ago

A machine gun fires 25 g bullets at the rate of 600 bullets per minute with a speed of 200 m/s. Calculate the force required to keep the gun in position.

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  1. Yahoo!
    • 2 years ago
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    600 bullets per minute = 600/60 = 10 bullets per second F = n * m * v = 10 * 200 * 25 * 10^-3 = 2N

  2. pratu043
    • 2 years ago
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    But force is rate of change of momentum right?

  3. Yahoo!
    • 2 years ago
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    sorry F=50N

  4. Mikael
    • 2 years ago
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    He gave you in fact Change of momentum/ per 1 sec

  5. Yahoo!
    • 2 years ago
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    My calcu was wrong..))

  6. pratu043
    • 2 years ago
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    I didn't get you @Mikael.

  7. Mikael
    • 2 years ago
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    See he calculated for U how much Momentum is given to ALL the bullets flying-out in the period of 1 second . IT IS the change in momentum of the gun too - with a minus sign of course

  8. RaphaelFilgueiras
    • 2 years ago
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    |dw:1346144826007:dw|

  9. RaphaelFilgueiras
    • 2 years ago
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    impulse is the variation of momentum

  10. RaphaelFilgueiras
    • 2 years ago
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    think in one bullet

  11. Rohangrr
    • 2 years ago
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    \[-- ♬ \ Jack \ of \ Oz \ ♬ \ [your \ turn] \]

  12. TheProf
    • 2 years ago
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    If the slowest rate of acceleration of a bullet is 0.1 seconds, then 0.025 x (200/0.1) [F = ma] = 50 N. So that would be the force from each fired bullet. We get the 0.1 second as the gun fires 10 rounds per second.

  13. ghazi
    • 2 years ago
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    force exerted by each bullet is impulsive therefore...force exerted by each bullet is 5 N that is the force which should be maintained to keep gun stationary

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