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Stats Question Real estate ads suggest that 63% of homes for sale have garages, 21% have pools, and 18% have both features. What is the probability that a home for sale has: a) A pool or garage? b) Neither a pool or garage? c) A pool but no garage?

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For a I have to use the formula: P(A) + P(B) - P(A n B) =
Yeah, my teacher drew that out for us today. I don't really get what goes in the formula for part a though.

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So the entire garage circle is 63% and the entire Pool circle is 21%. But these two percentages also contain the percentage of houses which have both. So you should add together the 63% and the 21%, and subtract the 18%, which is the intersection of A and B.
yeah i see that now.
for b, do i take 37 + 79 and then subtract 82?
or am i off?
I think you should just take the complement of your answer to A.
66% of houses have either a pool or a garage, so (1-0.66) = 0.44 will have none of these.
that's not it
i am given this formula though: P(A)=1-P(A^c)
Yeah, so 1-P(A)' = P(A), and this works the other way. 1-P(A) = P(A)'
it's 0.34. you subtracted wrong.
Haha oh dear, more coffee required. Sorry. Do you get the idea though?
yeah, i'm getting it slowly but surely. this is my first time taking stats and i just started, so i'm getting used to it.
My advice is to get the hang of drawing those Venn Diagrams. They are really helpful.
can you help me with part c too?
This area, right? |dw:1346194888234:dw|
is it 0.21-0.18?
sweet :)

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