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LoveToDance22

  • 2 years ago

Geometry, please help!

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  1. LoveToDance22
    • 2 years ago
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    A quadrilateral EFGH is drawn on a coordinate grid as shown below.

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  2. LoveToDance22
    • 2 years ago
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    Pamela will draw a quadrilateral IJKL similar to quadrilateral EFGH. The length of IJ should be 6 and I should be located at point (1, -3). At which points will vertices J and K be located?

  3. completeidiot
    • 2 years ago
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    do you know what similar means?

  4. LoveToDance22
    • 2 years ago
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    proportional sides and congruent angles?

  5. completeidiot
    • 2 years ago
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    right ijkl is similar to efgh this means ij is proportional to ef if ij is 6 and ef is 3, then what is the proportion

  6. LoveToDance22
    • 2 years ago
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    @completeidiot 6/3 so 3/1 ?

  7. completeidiot
    • 2 years ago
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    do you want to correct your mistake?

  8. LoveToDance22
    • 2 years ago
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    oh lol sorry 2/1

  9. completeidiot
    • 2 years ago
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    ok this means the sides of ijkl are 2 times larger than the sides of efgh you know where point I is so start by drawing that you also know where point J is which is 6 units away from I, so you can draw that look at efgh for information and keep plotting ijkl until you get a similar quadrilateral then make note of where point k and point l are

  10. LoveToDance22
    • 2 years ago
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    @completeidiot I got (3, 1) for J, and (5, -5) for K

  11. completeidiot
    • 2 years ago
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    G is 4 units to the right from F that means j is how many units away from k?

  12. completeidiot
    • 2 years ago
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    dont know where the post went but yes it is 8 units to the right, so you can draw K

  13. LoveToDance22
    • 2 years ago
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    oh sorry haha I though it was wrong so I deleted it

  14. completeidiot
    • 2 years ago
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    now do the same thing to find L

  15. LoveToDance22
    • 2 years ago
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    is it 10?

  16. completeidiot
    • 2 years ago
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    yes

  17. completeidiot
    • 2 years ago
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    now draw it on your graph and then you'll have a similar quadrilateral

  18. LoveToDance22
    • 2 years ago
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    thanks! :)

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