KE8717504
what are 2 binomials whose product is x^2-25?? please help
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AnimalAin
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Difference of squares. \[a^2-b^2=(a+b)(a-b) \]
KE8717504
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Ok so what would that make the binomials?
KE8717504
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I just hate binomials i can't ever get them.
lgbasallote
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a+ b <---first binomial
a - b<---second binomial
just substitue a and b to the right values
KE8717504
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Yes that's what I am having trouble finding though. Because the question states write 2 binomials whose product is x squared - 25
KE8717504
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I have no clue, i know that sounds stupid
KE8717504
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I just hate doing math anyways so it's confusing to me even when i do binomials.
lgbasallote
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okay here's a hint \[a^2 - b^2 \implies (a+b)(a-b)\]
so \[x^2 - 4 \implies (x + 2)(x-2)\]
\[x^2 - 9 \implies (x+3)(x-3)\]
\[x^2 - 16 \implies (x+4)(x-4)\]
are you getting it now?
KE8717504
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so a bionomial for x squared -25 could be (x+5)?
lgbasallote
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yes that's one of the binomials...what's the other?
KE8717504
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would it be (x-5)?
lgbasallote
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yes. the binomials for x^2 - 25 is (x+5)(x-5)
congrats
KE8717504
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well see when i typed that in my program on my computer i have to do this math on it said it was incorrect
lgbasallote
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that's why i hate those computers lol. so picky
lgbasallote
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try putting them in one by one
KE8717504
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i did i tried the x + 5 first
lgbasallote
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shouldnt make a difference but...try putting x-5 first?
KE8717504
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Should I put the ( ) or not?
KE8717504
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and it says type your answer in factor form so what would that be
lgbasallote
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(x+5)(x-5)
lgbasallote
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^factor form
KE8717504
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so the (x+5)(x-5) is factor form?
lgbasallote
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yes (x+5)(x-5) is factor form...
KE8717504
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can i ask you another math question
lgbasallote
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sure
KE8717504
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The number of ways a teacher can award different prizes to 2 students in class having n students is given by the formula p(n)=n(n-1)
KE8717504
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use this formula to determeine the number of ways a teacher can award different prizes to 2 students in a class having 6 students
lgbasallote
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substitute 6 into n in the formula
KE8717504
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then it says to rewrite the formula by multiplying the factors
lgbasallote
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yes. substitute 6 into n in the formula...
KE8717504
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ok so the formula would be P(6)=6(6-1)?
lgbasallote
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yes
KE8717504
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just a couple more questions i promise
KE8717504
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when i tried typing that the other way it said multiply the two factors of the expression for p(n) given in the problem statement to write the expression in a different way
lgbasallote
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i dont get what you're asking
KE8717504
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It's just saying to rewrite the formula in a different way
KE8717504
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by multiplying the factors
lgbasallote
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just substitute 6 into n...isnt that what you did?
KE8717504
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Yea i did that for the first answer but it's not right for the second one
lgbasallote
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now multiply
lgbasallote
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simplify it
KE8717504
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so the answer would be 30 right that simplified
KE8717504
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but that's not the formula
KE8717504
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can i give u my math xl login info and let you look at it?
lgbasallote
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the formula is what you wrote first
lgbasallote
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the simplified is the second answer
KE8717504
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So the first formula was p(n)=n(n-1) then it was P(6)=6(6-1) then it was P(6)=6(5) and then P(6)=30
lgbasallote
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yes
KE8717504
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But when it said to multiply factors and write the formula over I have no idea
lgbasallote
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multiply the factors means you multiply the factors <--that will give you 30
write the formula over is just copying the formula but substitute 6
KE8717504
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ok so my answer box already has P(N)= so i need to put 6 X 5
lgbasallote
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if the start is p(n) =
then you rewrite the formula... n(n-1)
KE8717504
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omg it said it wasn't in correct form that time but it was correct
lgbasallote
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lol. these computers are confusing me now o.O
KE8717504
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I know right I don't know how to put it
lgbasallote
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me neither.
lgbasallote
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sorry kid. cant help you with your computer problems.
lgbasallote
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i have to go now so i wish you luck that you finish this
KE8717504
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thanks soooo much for your help
lgbasallote
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welcome