Denebel
Can somebody check my work: complete the square for 20x^2  5q + 12.



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Denebel
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dw:1346221352232:dw

hartnn
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it must be 20x^25x+12

waterineyes
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Yes it is x there..

Denebel
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Oops, typo, yes you're right

waterineyes
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1/4x will be there..

waterineyes
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And it will be :
(x  1/8)^2 not (x  1/64)^2..

waterineyes
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\[x^2  \frac{1}{4}x + \frac{3}{5} = (x  \frac{1}{8})^2 + \frac{3}{5}  \frac{1}{64} = ??\]

Denebel
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Oops, thanks :) = (x1/8)^2  187/320 ?