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Denebel

  • 3 years ago

Can somebody check my work: complete the square for 20x^2 - 5q + 12.

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  1. Denebel
    • 3 years ago
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    |dw:1346221352232:dw|

  2. hartnn
    • 3 years ago
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    it must be 20x^2-5x+12

  3. waterineyes
    • 3 years ago
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    Yes it is x there..

  4. Denebel
    • 3 years ago
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    Oops, typo, yes you're right

  5. waterineyes
    • 3 years ago
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    -1/4x will be there..

  6. waterineyes
    • 3 years ago
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    And it will be : (x - 1/8)^2 not (x - 1/64)^2..

  7. waterineyes
    • 3 years ago
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    \[x^2 - \frac{1}{4}x + \frac{3}{5} = (x - \frac{1}{8})^2 + \frac{3}{5} - \frac{1}{64} = ??\]

  8. Denebel
    • 3 years ago
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    Oops, thanks :) = (x-1/8)^2 - 187/320 ?

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