## anonymous 3 years ago Can somebody check my work: complete the square for 20x^2 - 5q + 12.

1. anonymous

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2. hartnn

it must be 20x^2-5x+12

3. anonymous

Yes it is x there..

4. anonymous

Oops, typo, yes you're right

5. anonymous

-1/4x will be there..

6. anonymous

And it will be : (x - 1/8)^2 not (x - 1/64)^2..

7. anonymous

$x^2 - \frac{1}{4}x + \frac{3}{5} = (x - \frac{1}{8})^2 + \frac{3}{5} - \frac{1}{64} = ??$

8. anonymous

Oops, thanks :) = (x-1/8)^2 - 187/320 ?