Denebel Group Title Can somebody check my work: complete the square for 20x^2 - 5q + 12. 2 years ago 2 years ago

1. Denebel

|dw:1346221352232:dw|

2. hartnn

it must be 20x^2-5x+12

3. waterineyes

Yes it is x there..

4. Denebel

Oops, typo, yes you're right

5. waterineyes

-1/4x will be there..

6. waterineyes

And it will be : (x - 1/8)^2 not (x - 1/64)^2..

7. waterineyes

$x^2 - \frac{1}{4}x + \frac{3}{5} = (x - \frac{1}{8})^2 + \frac{3}{5} - \frac{1}{64} = ??$

8. Denebel

Oops, thanks :) = (x-1/8)^2 - 187/320 ?