## lizz17 Group Title Use the formula for the area of a trapezoid , where A is area, b1 and b2 are the length of the bases, and h is the height, to answer the question. How many square feet of grass are there on a trapezoidal field with a height of 75 ft and bases of 125 ft and 81 ft? one year ago one year ago

1. Traxter Group Title

Well, do you know the formula for the area of a trapezoid?

2. lizz17 Group Title

sorry about that it didnt copy.

3. lizz17 Group Title

A= h (b1+b2/2)

4. monokerous Group Title

$A={1 \over 2} \times (b1+b2) \times h$

5. monokerous Group Title

yes. Now plug in the values. b1=125, b2=81, h=75

6. monokerous Group Title

what do you get?

7. lizz17 Group Title

idk); i need the steps and all that with the response. ive been doing that problem for 2 hours and still havent got it

8. Traxter Group Title

You have A=1/2×(b1+b2)×h So just sub in your values of b1 and b2 (the lengths of the bases) and h (the height of the trapezoid). What can't you do?

9. lizz17 Group Title

wait let me tell u so you can tell me if i got it right

10. monokerous Group Title

I'll give you one example. I hope you understand so you can plug in the rest into the formula. $A=75({b1+b2 \over 2})$ I plugged in h=75 into the equation that you gave. Now, plug in b1 and b2 to solve.

11. monokerous Group Title

12. monokerous Group Title

Basically, their saying that the field is a trapezoid and they want to find the area of the field. What we're doing now is finding the area of the field.

13. lizz17 Group Title

A= h (b1+b2/2) A=75x(125x1+ 81x2/2) =125+6,561/2 =75x3,343 A=250,725 ehh im wrong huh? lol

14. monokerous Group Title

b1 and b2 are just names. You don't have to multiply

15. monokerous Group Title

it's short for 'base 1' and 'base 2'

16. monokerous Group Title

This should be your equation. $A=75({125+81 \over 2})$

17. monokerous Group Title

Can you solve it now? :)

18. lizz17 Group Title

19. monokerous Group Title

I can see why you were so confused. Solve the equation i gave. You're answer of 7,500 is close, but it's not correct.

20. lizz17 Group Title

A=75x(125+81/2) A=75x(206/2) A=75x103 A=7,725 I added right but isomehow made the 6 look like a 0. oopps

21. monokerous Group Title

yes. 7,725 is right! :)

22. monokerous Group Title

No worries. We all make mistakes now and then. ;)

23. lizz17 Group Title

Yay!!! Thankyou so much!!!

24. monokerous Group Title

You're welcome!