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rishabh.mission

  • 3 years ago

ans plz .. Topic-uniform circular motion qestion

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  1. rishabh.mission
    • 3 years ago
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    a partical moves horizontally in a uniform circular motion ,over a horizontal xy plane .At one instant ,it moves through the point at coordintate (4m , 4m) with a velocity of -5.0i m/s and an acceleration of +12.5j m/s(sqr) . what is the (a)x and (b) y coordinates of the center of the circular path?

  2. Mikael
    • 3 years ago
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    Hello

  3. Mikael
    • 3 years ago
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    the acceleration is v^2/R this helps u find the radius if you know acceleration and Velocity

  4. Yahoo!
    • 3 years ago
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    a = V^2/r

  5. Yahoo!
    • 3 years ago
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    r = V^2/a = 2

  6. Yahoo!
    • 3 years ago
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    x coordinate of the center is 4 straight up ...so find the radius and you'll have y coordinate as 2+4=6m

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