A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

jpjones
 2 years ago
Best ResponseYou've already chosen the best response.0z = x+iy this is complex number question

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1Well first of all you can find out that P(2)=0

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1Therefore z2 must be a factor of 2z^3  2z^2  z  6

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0There will be one + ve real root.)

jpjones
 2 years ago
Best ResponseYou've already chosen the best response.0why is it that you have fed 2 into the equation, is this a random number

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1When you try to factorize polynomials you can try plugging in numbers to see which one of them give you a zero, it is a trial and error way to factorize easily

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1So if P(2) gives you zero, z2 must be a factor of p(z)

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1Then when you divide 2z^3 + 2z^2z6 by z2

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0Sum of the Roots , product of the roots

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1So we have the following expression (2z^2 +2z +3)(z2)=0

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1Now we have found one solutions z = 2

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1Other two are given by 2z^2+2z+3=0

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0and the other sol^n will be Complex numbers...

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1I am going to complete the square

jpjones
 2 years ago
Best ResponseYou've already chosen the best response.0polynomials are fun aren't they

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0nop...@baddinlol use quadratic formula

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.12(z^2 + z + 3/2) = 0 z^2 + z + 3/2 = 0 (z + 1/2)^2 + 5/4 = 0

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1(z + 1/2)^2 = 5/4 z + 1/2 = sqrt(5)i /2, sqrt(5)i /2 z = (sqrt(5)i  1)/2, (1sqrt(5)i)/2

jpjones
 2 years ago
Best ResponseYou've already chosen the best response.0that will be =+orsqrt b^24(a)(c)/(2a)

jpjones
 2 years ago
Best ResponseYou've already chosen the best response.0well done baddinol thanks

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1Did you know about putting in numbers to find p(Z) = 0?

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1By the way the numbers you plug in have to be a factor of the constant in the equation, which in your equation is 6::::: 2z^32z^2z6

jpjones
 2 years ago
Best ResponseYou've already chosen the best response.0i did but i thought there must be a faster way

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1SO i tried 1, 1, 2 and when i got upto 2 i stopped because i found P(2)=0

baddinlol
 2 years ago
Best ResponseYou've already chosen the best response.1Are you allowed to use a cas calculator?
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.