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tux
 4 years ago
A∩(BC)=(A∩B)(A∩C). Using algebraic proof I got (A∩B)∩(AC).
tux
 4 years ago
A∩(BC)=(A∩B)(A∩C). Using algebraic proof I got (A∩B)∩(AC).

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1346329193067:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1346329377564:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1346329433857:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1346329493645:dwSimilarly, proceed step by step u will get

tux
 4 years ago
Best ResponseYou've already chosen the best response.0My problem is I need to prove it using set laws (commutative, associative ...)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Translate to set algebra \[\cup \rightarrow +\] dw:1346351911567:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1346351955786:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0translate to this notation your problem, THEN open all parantheses, THEN gather like terms, THEN translate back to Set theory notation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Also (forgoT)dw:1346352053975:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1346352107065:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1346352172712:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Whatever form is more convenient for the right hand side expression

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0USe also dw:1346352282882:dw

tux
 4 years ago
Best ResponseYou've already chosen the best response.0BC rewritten as B∩C^c A∩(B∩C^c) A rewritten as A∩A A∩A∩B∩C^c Associative law (A∩B)∩(A∩C^c) My result: (A∩B)∩(AC)

tux
 4 years ago
Best ResponseYou've already chosen the best response.0@sauravshakya We start with left side A∩(BC) and must prove (A∩B)(A∩C) Solution is (A∩B)(A∩C) which must be proved As a wrong result I got (A∩B)∩(AC).

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I suggest u try boolean algebra

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In the representation I have showed above all is solved easy

tux
 4 years ago
Best ResponseYou've already chosen the best response.0I am not allowed to use complement definition 1A

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@IAmCool Please do not go into other's threads asking for help on your question, it's considered spam.

zzr0ck3r
 4 years ago
Best ResponseYou've already chosen the best response.1@sauravshakya @tux @Mikael ....I think you guys were making this way to hard.
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