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tux
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A∩(BC)=(A∩B)(A∩C). Using algebraic proof I got (A∩B)∩(AC).
 2 years ago
 2 years ago
tux Group Title
A∩(BC)=(A∩B)(A∩C). Using algebraic proof I got (A∩B)∩(AC).
 2 years ago
 2 years ago

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sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
dw:1346329193067:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
dw:1346329377564:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
Now, A∩(BC)
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
dw:1346329433857:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
dw:1346329493645:dwSimilarly, proceed step by step u will get
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
Thus, proved
 2 years ago

tux Group TitleBest ResponseYou've already chosen the best response.0
My problem is I need to prove it using set laws (commutative, associative ...)
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
Translate to set algebra \[\cup \rightarrow +\] dw:1346351911567:dw
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
dw:1346351955786:dw
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
translate to this notation your problem, THEN open all parantheses, THEN gather like terms, THEN translate back to Set theory notation
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
Also (forgoT)dw:1346352053975:dw
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
dw:1346352107065:dw
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
dw:1346352172712:dw
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
Whatever form is more convenient for the right hand side expression
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
USe also dw:1346352282882:dw
 2 years ago

tux Group TitleBest ResponseYou've already chosen the best response.0
BC rewritten as B∩C^c A∩(B∩C^c) A rewritten as A∩A A∩A∩B∩C^c Associative law (A∩B)∩(A∩C^c) My result: (A∩B)∩(AC)
 2 years ago

tux Group TitleBest ResponseYou've already chosen the best response.0
@sauravshakya We start with left side A∩(BC) and must prove (A∩B)(A∩C) Solution is (A∩B)(A∩C) which must be proved As a wrong result I got (A∩B)∩(AC).
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
I suggest u try boolean algebra
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
In the representation I have showed above all is solved easy
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
shown (typo)
 2 years ago

tux Group TitleBest ResponseYou've already chosen the best response.0
I am not allowed to use complement definition 1A
 2 years ago

farmdawgnation Group TitleBest ResponseYou've already chosen the best response.0
@IAmCool Please do not go into other's threads asking for help on your question, it's considered spam.
 2 years ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
@sauravshakya @tux @Mikael ....I think you guys were making this way to hard.
 2 years ago
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