tux
  • tux
A∩(B-C)=(A∩B)-(A∩C). Using algebraic proof I got (A∩B)∩(A-C).
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1346329193067:dw|
anonymous
  • anonymous
|dw:1346329377564:dw|
anonymous
  • anonymous
Now, A∩(B-C)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
|dw:1346329433857:dw|
anonymous
  • anonymous
|dw:1346329493645:dw|Similarly, proceed step by step u will get
anonymous
  • anonymous
Thus, proved
tux
  • tux
My problem is I need to prove it using set laws (commutative, associative ...)
anonymous
  • anonymous
Translate to set algebra \[\cup \rightarrow +\] |dw:1346351911567:dw|
anonymous
  • anonymous
|dw:1346351955786:dw|
anonymous
  • anonymous
translate to this notation your problem, THEN open all parantheses, THEN gather like terms, THEN translate back to Set theory notation
anonymous
  • anonymous
Also (forgoT)|dw:1346352053975:dw|
anonymous
  • anonymous
|dw:1346352107065:dw|
anonymous
  • anonymous
|dw:1346352172712:dw|
anonymous
  • anonymous
Whatever form is more convenient for the right hand side expression
anonymous
  • anonymous
USe also |dw:1346352282882:dw|
tux
  • tux
B-C rewritten as B∩C^c A∩(B∩C^c) A rewritten as A∩A A∩A∩B∩C^c Associative law (A∩B)∩(A∩C^c) My result: (A∩B)∩(A-C)
tux
  • tux
@sauravshakya We start with left side A∩(B-C) and must prove (A∩B)-(A∩C) Solution is (A∩B)-(A∩C) which must be proved As a wrong result I got (A∩B)∩(A-C).
anonymous
  • anonymous
I suggest u try boolean algebra
anonymous
  • anonymous
In the representation I have showed above all is solved easy
anonymous
  • anonymous
shown (typo)
tux
  • tux
I am not allowed to use complement definition 1-A
farmdawgnation
  • farmdawgnation
@IAmCool Please do not go into other's threads asking for help on your question, it's considered spam.
zzr0ck3r
  • zzr0ck3r
@sauravshakya @tux @Mikael ....I think you guys were making this way to hard.
anonymous
  • anonymous
?
zzr0ck3r
  • zzr0ck3r

Looking for something else?

Not the answer you are looking for? Search for more explanations.