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tux
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A∩(BC)=(A∩B)(A∩C). Using algebraic proof I got (A∩B)∩(AC).
 one year ago
 one year ago
tux Group Title
A∩(BC)=(A∩B)(A∩C). Using algebraic proof I got (A∩B)∩(AC).
 one year ago
 one year ago

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sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
dw:1346329193067:dw
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
dw:1346329377564:dw
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
Now, A∩(BC)
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
dw:1346329433857:dw
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
dw:1346329493645:dwSimilarly, proceed step by step u will get
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
Thus, proved
 one year ago

tux Group TitleBest ResponseYou've already chosen the best response.0
My problem is I need to prove it using set laws (commutative, associative ...)
 one year ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
Translate to set algebra \[\cup \rightarrow +\] dw:1346351911567:dw
 one year ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
dw:1346351955786:dw
 one year ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
translate to this notation your problem, THEN open all parantheses, THEN gather like terms, THEN translate back to Set theory notation
 one year ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
Also (forgoT)dw:1346352053975:dw
 one year ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
dw:1346352107065:dw
 one year ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
dw:1346352172712:dw
 one year ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
Whatever form is more convenient for the right hand side expression
 one year ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
USe also dw:1346352282882:dw
 one year ago

tux Group TitleBest ResponseYou've already chosen the best response.0
BC rewritten as B∩C^c A∩(B∩C^c) A rewritten as A∩A A∩A∩B∩C^c Associative law (A∩B)∩(A∩C^c) My result: (A∩B)∩(AC)
 one year ago

tux Group TitleBest ResponseYou've already chosen the best response.0
@sauravshakya We start with left side A∩(BC) and must prove (A∩B)(A∩C) Solution is (A∩B)(A∩C) which must be proved As a wrong result I got (A∩B)∩(AC).
 one year ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
I suggest u try boolean algebra
 one year ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
In the representation I have showed above all is solved easy
 one year ago

Mikael Group TitleBest ResponseYou've already chosen the best response.0
shown (typo)
 one year ago

tux Group TitleBest ResponseYou've already chosen the best response.0
I am not allowed to use complement definition 1A
 one year ago

farmdawgnation Group TitleBest ResponseYou've already chosen the best response.0
@IAmCool Please do not go into other's threads asking for help on your question, it's considered spam.
 one year ago

zzr0ck3r Group TitleBest ResponseYou've already chosen the best response.1
@sauravshakya @tux @Mikael ....I think you guys were making this way to hard.
 one year ago
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